Last visit was: 25 Apr 2026, 06:04 It is currently 25 Apr 2026, 06:04
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Sajjad1994
User avatar
GRE Forum Moderator
Joined: 02 Nov 2016
Last visit: 24 Apr 2026
Posts: 16,772
Own Kudos:
51,921
 [4]
Given Kudos: 6,334
GPA: 3.62
Products:
GMAT Club Tests Forum Quiz
Posts: 16,772
Kudos: 51,921
 [4]
If the square in the figure BELOW is rotated clockwise about th 06 Jun 2017, 03:40
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

35% (medium)

Question Stats:

65% (01:32) correct 35% (01:17) wrong based on 116 sessions

History

Date
Time
Result
Not Attempted Yet
If the square in the figure BELOW is rotated clockwise about the origin until vertex V is on the negative y-axis, then the new y-coordinate of V is

(A) –2
(B) −2 \(\sqrt{2}\)
(C) –4
(D) −3 \(\sqrt{2}\)
(E) –8

Source: Nova GMAT
Difficulty Level: 600
ShowHide Answer
Official Answer
B

Attachments

BHGVF.jpg
BHGVF.jpg [ 6.08 KiB | Viewed 4456 times ]

User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 25 Apr 2026
Posts: 6,977
Own Kudos:
16,916
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,977
Kudos: 16,916
 [1]
If the square in the figure BELOW is rotated clockwise about th 06 Jun 2017, 04:14
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
SajjadAhmad
If the square in the figure BELOW is rotated clockwise about the origin until vertex V is on the negative y-axis, then the new y-coordinate of V is

(A) –2
(B) −2 \(\sqrt{2}\)
(C) –4
(D) −3 \(\sqrt{2}\)
(E) –8

Nova GMAT
Show more

Distance of V from origin = \(\sqrt{{2^2+2^2}\) = \(2\sqrt{2}\)

The distance of V from origin will remain same as the Vertex V will follow the locus of a circle with radius \(2\sqrt{2}\)

Hence the co ordinate of V on negative Y axis = (0, \(-2\sqrt{2}\))

Answer: Option B
User avatar
arvind910619
User avatar
Joined: 20 Dec 2015
Last visit: 18 Oct 2024
Posts: 814
Own Kudos:
615
Given Kudos: 755
Status:Learning
Location: India
Concentration: Operations, Marketing
GMAT 1: 670 Q48 V36
GRE 1: Q157 V157
GPA: 3.4
WE:Engineering (Manufacturing)
Products:
My Reviews
GMAT 1: 670 Q48 V36
GRE 1: Q157 V157
Posts: 814
Kudos: 615
If the square in the figure BELOW is rotated clockwise about th 06 Jun 2017, 04:32
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IMO B

Distance of v from origin is 2*sqrt(2)
So if it is rotated x coordinate will become 0 and y will be -2*sqrt(2)
User avatar
BeingHan
User avatar
Joined: 30 Mar 2017
Last visit: 01 Feb 2026
Posts: 51
Own Kudos:
62
Given Kudos: 39
Posts: 51
Kudos: 62
If the square in the figure BELOW is rotated clockwise about th 06 Jun 2017, 04:37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
B.The new vertex will be at the same distance from the origin and the old vertex. Which is sqrt 8 units. And only B satisfies it.

Sent from my Moto G (5) Plus using GMAT Club Forum mobile app
User avatar
generis
User avatar
Senior SC Moderator
Joined: 22 May 2016
Last visit: 18 Jun 2022
Posts: 5,258
Own Kudos:
37,729
Given Kudos: 9,464
Expert
Expert reply
Posts: 5,258
Kudos: 37,729
If the square in the figure BELOW is rotated clockwise about th 06 Jun 2017, 06:20
Kudos
Add Kudos
Bookmarks
Bookmark this Post
SajjadAhmad
If the square in the figure BELOW is rotated clockwise about the origin until vertex V is on the negative y-axis, then the new y-coordinate of V is

(A) –2
(B) −2 \(\sqrt{2}\)
(C) –4
(D) −3 \(\sqrt{2}\)
(E) –8

Nova GMAT
Show more

In rotation problems, often it's easier to "see" what to track as a figure moves by drawing it. Connect V to Origin.

That's the line that whose rotated end point is the target. It is the distance from V to origin.

It is also the hypotenuse of a smaller isosceles right triangle in quadrant IV with side ratio of \(x : x : \sqrt{2}\). From (x2 - x1)*, side is 2. Hence hypotenuse is 2\(\sqrt{2}\), which = the absolute value of y on the rotated vertex, which will lie on the negative y-axis.

So y-coordinate is −2 \(\sqrt{2}\).

Answer B

* x2 is from V, x1 is from lower left vertex (0, -2) of small square in Q4
avatar
nissstheone
avatar
Joined: 26 May 2019
Last visit: 03 Nov 2019
Posts: 7
Own Kudos:
1
Given Kudos: 12
Posts: 7
Kudos: 1
If the square in the figure BELOW is rotated clockwise about th 16 Jun 2019, 23:02
Kudos
Add Kudos
Bookmarks
Bookmark this Post
when we rotate the square to the negative y axis - it will become the diagonal of the square.

therefore we can answer this question within 10 seconds.

diagonal of square = sqrt2 * side of square.
Moderators:
Bunuel
Math Expert
109826 posts
Krunaal
Tuck School Moderator
852 posts