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# If the sum of four consecutive integers is 66, what is the greatest of

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If the sum of four consecutive integers is 66, what is the greatest of [#permalink]
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Bunuel wrote:
If the sum of four consecutive integers is 66, what is the greatest of these integers?

A. 14
B. 15
C. 16
D. 17
E. 18

PS21196

In case of consecutive Integers, FIrst + FOrth = Second + third term

i.e. Second + third = 66/2 = 33

Two consecutive integers sum = 33 i.e. second = 16 and third = 17

ie. Forth = 18

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Re: If the sum of four consecutive integers is 66, what is the greatest of [#permalink]
Bunuel wrote:
If the sum of four consecutive integers is 66, what is the greatest of these integers?

A. 14
B. 15
C. 16
D. 17
E. 18

PS21196

$$( a - 1 ) + a + ( a + 1 ) + ( a + 2 ) = 66$$

Or, $$4a + 2 = 66$$

Or, $$4a = 64$$

So, a = 16 Thus, the greatest number must be 16 + 2 = 18 , Answer must be (D)
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Re: If the sum of four consecutive integers is 66, what is the greatest of [#permalink]
Bunuel wrote:
If the sum of four consecutive integers is 66, what is the greatest of these integers?

A. 14
B. 15
C. 16
D. 17
E. 18

PS21196

4 consective terms
x,x+1, x+2 , x+3 ;
sum = 4x+6 = 66
x= 15 so greatest term ; 15+3 ; 18
OPTION E
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Re: If the sum of four consecutive integers is 66, what is the greatest of [#permalink]