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Bunuel
If two die, each numbered one through five, are rolled, what is the probability that the sum of the two numbers will be prime?

A. 16/25
B. 11/25
C. 8/25
D. 7/25
E. 1/5

The answer is 7/25

The prime sum can be 2 ,3 , and 5
For 2 we have only 1 choice (1,1)
For 3 we have 2 choices ( 2,1) and (1,2)
For 5 also we have 4 choices (2,3) ,(3,2) , (4,1) and (1,4)
Favorable outcomes =7
Total number of outcomes =25
Therefor the probability=7/25
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Bunuel
If two die, each numbered one through five, are rolled, what is the probability that the sum of the two numbers will be prime?

A. 16/25
B. 11/25
C. 8/25
D. 7/25
E. 1/5

A prime sum can happen in the following ways:

A sum of 2: (1, 1)

A sum of 3: (1, 2) and (2, 1)

A sum of 5: (1, 4), (4, 1), (2, 3), and (3, 2)

A sum of 7: (2, 5), (5, 2), (3, 4), and (4, 3)

We observe that there are 11 favorable outcomes out of a total of 5 x 5 = 25 outcomes. Thus, the probability of a prime sum is 11/25.

Answer: B
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Hello from the GMAT Club BumpBot!

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