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22 May 2020, 08:56
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D
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Difficulty:
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84% (00:49) correct
16%
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wrong
based on 213
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If x > 0 and x^2 = 248, what is the closest integer approximation of x ?
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
Updated on: 22 May 2020, 09:00
Originally posted by BrentGMATPrepNow on 22 May 2020, 08:58.
Last edited by BrentGMATPrepNow on 22 May 2020, 09:00, edited 1 time in total.
Last edited by BrentGMATPrepNow on 22 May 2020, 09:00, edited 1 time in total.
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Bunuel
If x > 0 and x² = 248, what is the closest integer approximation of x ?
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
Let's find some perfect squares that are CLOSE to 248
15² = 225
16² = 256
Since 248 is closer to 256, we know that the value of x is close to 16
Answer: D
Cheers,
Brent
General Discussion
22 May 2020, 08:59
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Bookmarks
Bunuel
If x > 0 and x^2 = 248, what is the closest integer approximation of x ?
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
A. 496
B. 124
C. 50
D. 16
E. 14
PS21163
x^2 = 248
i.e. x ≈ 15.8
ANswer: Option D
