Hi vrinda6,I can see exactly where the logic flipped, and it's a really common one. You wrote that "whatever option we pick, all of its values should answer the question stem." That's the reverse of what a
must be true question asks - and fixing that one direction settles the whole thing.
Which way the arrow pointsThe question isn't asking:
do all the values in the option satisfy the inequality? It's asking:
for every x that satisfies the inequality, is this statement always true?So the master range is your solution set:
-3 < x < 7 (as the earlier solutions established). The correct option must be a statement that holds for
every single x in that range.
-
C) x > -4: Take any x from
-3 up to
7. Is it greater than
-4? Always yes - the smallest values (like
-2.9,
-2,
-1) are all still above
-4. So C is true for the
entire range. ✓
-
D) 0 < x < 3: Now test the
whole range against D. x =
-1 is a valid solution to the inequality (|-1 - 2| =
3 <
5), but
-1 is
not between
0 and
3. So D fails for part of the range. ✗
That's the key: D's values do fit inside the range, but plenty of valid x values fall
outside D. "All of D's values work" isn't what's being tested - "all valid x values satisfy the statement" is.
A quick parallel to lock the direction inSuppose you're told
x is an even number and asked what
must be true:
- "x is an integer" - true for
every even number. ✓ (this is the C-type answer)
- "x =
4" - sure,
4 is even, but not every even number is
4. ✗ (this is the D-type trap)
The right answer is the wider net that catches all cases - not the narrow one that only some cases fall into. Same reasoning makes
C the answer here.
Answer: Cvrinda6
I still believe that the right answer to this question just might be Option D.
This becomes a must be true question set which essentially means whatever option set that we do pick up, ideally all of the values should answer the question stem.
Option C satisfies every value above -3 and does not hold true for -3. But option D choices, all of them hold true and fall under must be tru.