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If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 03:34
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88% (00:42) correct 12% (01:15) wrong based on 129 sessions
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Re: If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 03:50
It should be C A is not possible cuz y is ve & x is +ve B  the ans can be 1 ex. (3/3) D x+y can be negetive E xy is always ve



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Re: If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 04:02
x > 2 and y < 2 A) x/y > 1 > Answer cannot be positive as we are dealing with opposite signs by x,y B) x/y < 1 > let's pick some extreme numbers x=2,1 and y=1,9 than x/y =1.1 YES , but x=5, y=10 x/y=0.5 NO C) x/y < 0 > CORRECT D) x + y > 0 > X=3, y=1 YES, x=3, y=100 NO E) xy > 0 > same as A
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Re: If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 04:15
The answer is C
x equals any value from 2 to infinity while y includes values from 2 to infinity. this value will always be less than zero as their signs will always be different irrespective of values.



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Re: If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 06:28
Pick x=3, y = 3 A) x/y > 1  Incorrect as x/y = 1 B) x/y < 1  Incorrect as x/y = 1 C) x/y < 0  Correct. It will hold for all values x > 2 and y < 2 as x/y = 1 < 0 D) x + y > 0  Incorrect. x + y = 0 E) xy > 0  Incorrect. XY = 9 which is less than zero.
C should be the answer.



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If x > 2 and y < 2, then which of the following must be true ?
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29 Sep 2015, 09:28
Bunuel wrote: If x > 2 and y < 2, then which of the following must be true ?
A) x/y > 1 B) x/y < 1 C) x/y < 0 D) x + y > 0 E) xy > 0
Kudos for a correct solution. My solution:
Stem says: x is +ve and greater than 2, y is ve and less than 2.
A) x/y>1 (can never be greater than 1 as expression will always be negative as y is negative. Not true )
B) x/y < 1 (can be equal to 1 when x is 3 and y is 3. Not true always)
C) x/y < 0 (will always be less than zero as only one value is negative i.e, "y". Always true.
D) x+y>0 (can be equal to zero or less than zero [3+(3)=0] or [4+(5)=1] Not always true)
E) xy>0(As y is negative xy can never be greater than zero. Not true)
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If x > 2 and y < 2, then which of the following must be true ?
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30 Sep 2015, 11:08
I believe the answer is C. Please see below for explanation.
If x > 2 and y < 2, then which of the following must be true ?
if x= 3 and y =3 and we plug in the numbers we get
A) x/y > 1 3/3=1 not true B) x/y < 1 3/3=1 not true C) x/y < 0 3/3=1 a positive number divided by a negative number will always be negative True D) x + y > 0 33=0 not true E) xy > 0 3*3<0 not true
Answer C



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Re: If x > 2 and y < 2, then which of the following must be true ?
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19 Dec 2017, 10:14
Bunuel wrote: If x > 2 and y < 2, then which of the following must be true ?
A) x/y > 1 B) x/y < 1 C) x/y < 0 D) x + y > 0 E) xy > 0
Kudos for a correct solution. Hi chetan2u & genxer123, For this question its obvious that the answer will be C. But I am unable to justify why D is wrong even though we can prove that D is wrong by plugging in some numbers. From the given question x > 2 and 2 > y. As I understand we can add and substract inequalities provided we know their sign. So, when we subtract the above two equation we get x + 2 > 2  y or x+y > 0. Can you please advise where I am wrong in my thinking.
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If x > 2 and y < 2, then which of the following must be true ?
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19 Dec 2017, 14:03
rahul16singh28 wrote: Bunuel wrote: If x > 2 and y < 2, then which of the following must be true ?
A) x/y > 1 B) x/y < 1 C) x/y < 0 D) x + y > 0 E) xy > 0
Kudos for a correct solution. Hi chetan2u & genxer123, For this question its obvious that the answer will be C. But I am unable to justify why D is wrong even though we can prove that D is wrong by plugging in some numbers. From the given question x > 2 and 2 > y. As I understand we an add and substract inequalities provided we know their sign. So, when we subtract the above two equation we get x + 2 > 2  y or x+y > 0. Can you please advise where I am wrong in my thinking. rahul16singh28 , you just got a little mixed up about the direction of the sign. (Take comfort: the answer is there because plenty of others will do exactly what you did.) It looks to me as if you subtracted inequalities with the same sign. You said you subtracted these: x > 2 and 2 > y Not allowed. Their signs face the same direction. We can add inequalities whose signs are the same direction. We can subtract inequalities whose signs are in opposite directions. So you can add the two you listed. And: You are adding a negative number (2) on LHS, i.e., subtraction. 3 + 2 = (32) = 1 ····· x > 2 (+)2 > y  = x  2 > 2 + y Can you take it from there? If not, you might want to take a look at Bunuel , Tips and Hints on InequalitiesAnd here, Inequalities Made EasyJust in case you haven't seen it, the GMATclub Math Book, IS HEREDoes that help?
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Re: If x > 2 and y < 2, then which of the following must be true ?
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19 Dec 2017, 19:49
rahul16singh28 wrote: Bunuel wrote: If x > 2 and y < 2, then which of the following must be true ?
A) x/y > 1 B) x/y < 1 C) x/y < 0 D) x + y > 0 E) xy > 0
Kudos for a correct solution. Hi chetan2u & genxer123, For this question its obvious that the answer will be C. But I am unable to justify why D is wrong even though we can prove that D is wrong by plugging in some numbers. From the given question x > 2 and 2 > y. As I understand we can add and substract inequalities provided we know their sign. So, when we subtract the above two equation we get x + 2 > 2  y or x+y > 0. Can you please advise where I am wrong in my thinking. Already explained above .... Just remember that you do not know the signs of variables.. So look at the sign and add the greater quantities and add the smaller quantities, ofcourse sum of greater quantities will be MORE than the sum of smaller quantities.. So x>2 and 2>y tells you x ia POSITIVE and y is NEGATIVE.. So 2y will become a positive value.
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