Bunuel
If \(|x + 2| = |x|\), how many values of \(x\) satisfy this equation?
A. 0
B. 1
C. 2
D. 3
E. 4
Method-1: Just think LogicallyGiven: \(|x + 2| = |x|\)
- This is possible only if adding two units to the value of x doesn't change the absolute value
- Which is possible only if the value is turning from negative to positive
- Now, we need to think of two values that are 2 units apart but are the same in absolute values
and I can think of -1 and +1
i.e. x = -1
i.e. one value
Answer: Option B
Method-2: Solve MathmaticallyGiven: \(|x + 2| = |x|\)
i.e. ±(x+2) = ±x
Case 1: +(x+2) = +x i.e. 2 = 0 NOT POSSIBLE
Case 2: +(x+2) = -x i.e. x = -1 First solution
Case 3: -(x+2) = +x i.e. x = 2 NOT POSSIBLE as it doesn't satisfy the primary equation on substituting back
Case 4: -(x+2) = -x i.e. -2 = 0 NOT POSSIBLE
Hence, one solution
Answer: Option B