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If x > 5,999 , then the value of 2x / (5x+1) is closest to which of

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New post 10 Aug 2019, 15:29
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If x > 5,999 , then the value of \(\frac{2x}{(5x+1)}\) is closest to which of the following?


(A) \(\frac{2}{7}\)

(B) \(\frac{2}{5}\)

(C) \(\frac{12}{21}\)

(D) \(\frac{12}{6}\)

(E) \(\frac{12}{5}\)

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Re: If x > 5,999 , then the value of 2x / (5x+1) is closest to which of  [#permalink]

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New post 10 Aug 2019, 16:13
For higher values of x, 5x+1 ≈ 5x

\(\frac{2x}{5x+1}\) ≈ \(\frac{2x}{5x}\)= \(\frac{2}{5}\)


MikeScarn wrote:
If x > 5,999 , then the value of \(\frac{2x}{(5x+1)}\) is closest to which of the following?


(A) \(\frac{2}{7}\)

(B) \(\frac{2}{5}\)

(C) \(\frac{12}{21}\)

(D) \(\frac{12}{6}\)

(E) \(\frac{12}{5}\)
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If x > 5,999 , then the value of 2x / (5x+1) is closest to which of  [#permalink]

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New post 10 Aug 2019, 16:59
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x > 5,999, let's take x=10,000.

2x/(5x+1) = 20,000/50,001 is about 2/5.

Answer is (B)

+1 kudo if you like my explanation
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Re: If x > 5,999 , then the value of 2x / (5x+1) is closest to which of  [#permalink]

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New post 11 Aug 2019, 02:47
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Re: If x > 5,999 , then the value of 2x / (5x+1) is closest to which of   [#permalink] 11 Aug 2019, 02:47
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