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22 May 2020, 08:41
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:09) correct
7%
(01:51)
wrong
based on 335
sessions
History
Date
Time
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Not Attempted Yet
If x(a + b) = y, where y ≠ 0 and 2a = 3b = 1, then y/x =
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
22 May 2020, 08:43
Kudos
Bookmarks
Bunuel
If x(a + b) = y, where y ≠ 0 and 2a = 3b = 1, then y/x =
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
x(a + b) = y
i.e. y/x = (a+b)
Given, 2a = 3b = 1
i.e. a = 1/2 and b = 1/3
i.e. a+b = 1/2 + 1/3 = 5/6
Answer: Option D
22 May 2020, 08:47
Kudos
Bookmarks
Bunuel
If x(a + b) = y, where y ≠ 0 and 2a = 3b = 1, then y/x =
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6
(E) 6/5
PS21159
Given: 2a = 1
Divide both sides by 2 to get: a = 1/2
Given: 3b = 1
Divide both sides by 3 to get: b = 1/3
Given: x(a + b) = y
Substitute to get: x(1/2 + 1/3) = y
Rewrite with common denominators: x(3/6 + 2/6) = y
Simplify: (x)(5/6) = y
Divide both sides by x to get: 5/6 = y/x
Answer: D
Cheers,
Brent
