\(x^2+11x\) will be even IRRESPECTIVE of x..
If x is ODD.. O^2+11*O= O+O=E
If x is EVEN..E^2+11*E=E+E=E..

So \(x^2+11x+13y\) depends on value of y only ..
If y is Odd, E+13*O=O
If y is Even, E+13*E=E

Let's see statement..
I. x=11..
Nothing about y..
Insufficient
II. y=13
So ans is Odd..
Suff

B

=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question, and then recheck the question.

Now, \(x^2+11x+13y = x(x+11)+13y\). As \(x(x+11)\) is always an even integer (one of \(x\) and [mx + 11[/m] must be even), \(x^2+11x+13y\) is even precisely when \(13y\) is even. This is equivalent to \(y\) being even, so the question can be restated as ‘Is \(y\) an even number?’.

Condition 1)
If \(x = 11\) and \(y = 1\), then \(x^2+11x+13y = 255\) is an odd integer.
If \(x = 11\) and \(y = 2\), then \(x^2+11x+13y = 268\) is an even integer.
Since the question does not have a unique answer, condition 1) is not sufficient.

Condition 2)
If \(y = 13\), then \(y\) is odd, and the answer to the question is ‘no’.
Condition 2) is sufficient.


Therefore, B is the answer.

Answer: B
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