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Bunuel
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If x and y are integers, is x positive? (1) x = |y| (2) x! = |x| 14 Jan 2017, 05:30
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Difficulty:

55% (hard)

Question Stats:

48% (01:01) correct 52% (01:28) wrong based on 98 sessions

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If x and y are integers, is x positive?

(1) x = |y|
(2) x! = |x|
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B
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If x and y are integers, is x positive? (1) x = |y| (2) x! = |x| 14 Jan 2017, 06:18
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1) for any value of y, X comes out to be +ve.. so sufficient
2) this will be true only for X equals 1 or 2
M not sure how in case of -ve value the second statement would work


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If x and y are integers, is x positive? (1) x = |y| (2) x! = |x| 14 Jan 2017, 06:49
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For x to be positive, x cannot take 0 as well. In the first case x can take 0 value and x is clearly negative in second case so neither of the two is sufficient to explain x is positive.
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If x and y are integers, is x positive? (1) x = |y| (2) x! = |x| 15 Jan 2017, 06:34
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If x and y are integers, is x positive?

(1) x = |y|

For any negative or positive number X will be always be positive.........the answer is Yes

However, if y and x equal to 0, then X is not positve............................the answer is NO.

P.S. ZERO is Integer but neither positive nor negative.

Insufficient

(2) x! = |x|

This statement implies that x is either 1 or 2. It is always positive.

P.S.: 0! = 1 and is NOT 0

Sufficient

Answer: B
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If x and y are integers, is x positive? (1) x = |y| (2) x! = |x| 15 Jan 2017, 08:07
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Bunuel
If x and y are integers, is x positive?

(1) x = |y|
(2) x! = |x|


From Statement 1, x can be 0 or Positive Integer
Statement is not Sufficient to confirm x > 0

From Statement 1, x can't be negative because factorial for negative numbers are not possible .
x must be a positive integer because if x = 0 then 0! = 1 = |x| = |0| is not possible .
x is a positive integer .
Statement 2 is sufficient

Answer is B .
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Bunuel
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