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If x and y are negative integers, which of the following must be true?

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If x and y are negative integers, which of the following must be true?  [#permalink]

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New post Updated on: 31 Oct 2018, 22:23
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If x and y are negative integers, which of the following must be true?

I. \(x - y > 0\)
II. \(\frac{x}{y} > y\)
III. \(x^2 > y\)

A. I only
B. II only
C. III only
D. I and III
E. II and III

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Originally posted by pushpitkc on 31 Oct 2018, 18:12.
Last edited by Bunuel on 31 Oct 2018, 22:23, edited 2 times in total.
Edited the question and the tags.
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Re: If x and y are negative integers, which of the following must be true?  [#permalink]

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New post 31 Oct 2018, 23:29
X and Y are -ve integers

(I) x - y>0
Case 1: x=-2 and y =-3
-2+3 = 1>0 (YES)
Case 2: x=-3 and y=-2
-3+2 = -1>0 (NO)

Hence A & D can be ruled out

(II) x/y >y
Case 1: x= -2 and y=-3
-2/-3 > -3
0.66 > -3 (YES)

LHS will be always positive since numerator and denominator are -ve and RHS is always -ve
Hence it must be true

(III) x^2>y
Case 1: x = -2 and y=-3
=>(-2)^2>-3
=>4>-3

This case is always true because a -ve integer will turn +ve once squared and RHS will be always -ve
Hence it must be true

Answer IMO is E
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Re: If x and y are negative integers, which of the following must be true?  [#permalink]

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New post 10 Nov 2018, 02:30
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pushpitkc wrote:
If x and y are negative integers, which of the following must be true?

I. \(x - y > 0\)
II. \(\frac{x}{y} > y\)
III. \(x^2 > y\)

A. I only
B. II only
C. III only
D. I and III
E. II and III



both x and y are negative.

I. x - y>0. could be when negative y is greater than negative x. Here we have to be careful about sign.

II. all time true. whenever we divide a negative number by another it yields positive one. thus the result will be greater than negative y.

III.\(x^2\)= positive. True.
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Re: If x and y are negative integers, which of the following must be true?   [#permalink] 10 Nov 2018, 02:30
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If x and y are negative integers, which of the following must be true?

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