Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 11 Dec 2013
Posts: 121
Location: India
GMAT Date: 03152015
WE: Education (Education)

If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
28 Jan 2019, 00:36
Question Stats:
34% (01:43) correct 66% (01:51) wrong based on 73 sessions
HideShow timer Statistics
If x and y are nonzero numbers such that x > y, which of the following is always true? A) \(\frac{1}{x} < \frac{1}{y}\) B) \(\frac{x}{y} > 1\) C) \(x > y\) D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\) E) \(\frac{x}{y} < \frac{y}{x}\)
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
KUDOS will increase your score



Director
Joined: 09 Mar 2018
Posts: 994
Location: India

If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
28 Jan 2019, 09:59
4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) IMO D Just test values, Given x > y If x and y are nonzero numbers Test values : 2> 1 or 1 > 2 A) \(\frac{1}{x} < \frac{1}{y}\), To avoid any confusion, always do this. \(\frac{1}{y} > \frac{1}{x}\), this works for me C1: 1 > 0.5, Yes C2: 1 > 0.5 No B) \(\frac{x}{y} > 1\) C1: 2 > 1 Yes C2: 0.5 > 1 No C) \(x > y\) This will give multiple values D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\), same here as well \(\frac{1}{x^2y} > \frac{1}{xy^2}\) For any set of values, Here i am always getting a No. E) \(\frac{x}{y} < \frac{y}{x}\)[/quote], same here as well \(\frac{y}{x} > \frac{x}{y}\)[/quote] Here you can get a Yes and a No
_________________
If you notice any discrepancy in my reasoning, please let me know. Lets improve together.
Quote which i can relate to. Many of life's failures happen with people who do not realize how close they were to success when they gave up.



Manager
Joined: 02 Jan 2017
Posts: 59
Location: India

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
30 Jan 2019, 03:55
4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) Can someone tell me why C is wrong



NUS School Moderator
Joined: 18 Jul 2018
Posts: 1020
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
30 Jan 2019, 04:04
AlN wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) Can someone tell me why C is wrong If you take x as 2 and y as 3. We can see that x > y as 2 > 3. But x = 2 and y = 3. And x is not greater than y. Hence C is wrong Posted from my mobile device
_________________
Press +1 Kudos If my post helps!



Intern
Joined: 25 Nov 2018
Posts: 2

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
30 Jan 2019, 08:19
KanishkM wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) IMO D Just test values, Given x > y If x and y are nonzero numbers Test values : 2> 1 or 1 > 2 A) \(\frac{1}{x} < \frac{1}{y}\), To avoid any confusion, always do this. \(\frac{1}{y} > \frac{1}{x}\), this works for me C1: 1 > 0.5, Yes C2: 1 > 0.5 No B) \(\frac{x}{y} > 1\) C1: 2 > 1 Yes C2: 0.5 > 1 No C) \(x > y\) This will give multiple values D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\), same here as well \(\frac{1}{x^2y} > \frac{1}{xy^2}\) For any set of values, Here i am always getting a No. E) \(\frac{x}{y} < \frac{y}{x}\) , same here as well \(\frac{y}{x} > \frac{x}{y}\)[/quote] Here you can get a Yes and a No[/quote] If D is giving a NO with every set of values of x and y. How come is D the right answer? Isnt te question stem asking for an option which is always true??



Director
Joined: 09 Mar 2018
Posts: 994
Location: India

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
30 Jan 2019, 12:24
hannan4644 wrote: KanishkM wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) IMO D Just test values, Given x > y If x and y are nonzero numbers Test values : 2> 1 or 1 > 2 A) \(\frac{1}{x} < \frac{1}{y}\), To avoid any confusion, always do this. \(\frac{1}{y} > \frac{1}{x}\), this works for me C1: 1 > 0.5, Yes C2: 1 > 0.5 No B) \(\frac{x}{y} > 1\) C1: 2 > 1 Yes C2: 0.5 > 1 No C) \(x > y\) This will give multiple values D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\), same here as well \(\frac{1}{x^2y} > \frac{1}{xy^2}\) For any set of values, Here i am always getting a No. E) \(\frac{x}{y} < \frac{y}{x}\) , same here as well \(\frac{y}{x} > \frac{x}{y}\) Here you can get a Yes and a No[/quote] If D is giving a NO with every set of values of x and y. How come is D the right answer? Isnt te question stem asking for an option which is always true??[/quote] Though i am not an expert, but i believe if we look at the rest of the options, we are able to negate this option completely with the same test cases. What one can try is to look for other options which will satisfy D, for different test cases. But i doubt that will happen, under the stipulated time limit of trying to solve a question in 23 minutes. Let me know if this helps you in anyway Posted from my mobile device
_________________
If you notice any discrepancy in my reasoning, please let me know. Lets improve together.
Quote which i can relate to. Many of life's failures happen with people who do not realize how close they were to success when they gave up.



Intern
Status: when you say,"I can or I can't", Both times you are right!
Joined: 26 Nov 2018
Posts: 31
Location: India

If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
03 Feb 2019, 07:15
hannan4644 wrote: KanishkM wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) IMO D Just test values, Given x > y If x and y are nonzero numbers Test values : 2> 1 or 1 > 2 A) \(\frac{1}{x} < \frac{1}{y}\), To avoid any confusion, always do this. \(\frac{1}{y} > \frac{1}{x}\), this works for me C1: 1 > 0.5, Yes C2: 1 > 0.5 No B) \(\frac{x}{y} > 1\) C1: 2 > 1 Yes C2: 0.5 > 1 No C) \(x > y\) This will give multiple values D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\), same here as well \(\frac{1}{x^2y} > \frac{1}{xy^2}\) For any set of values, Here I am always getting a No. E) \(\frac{x}{y} < \frac{y}{x}\) , same here as well \(\frac{y}{x} > \frac{x}{y}\) D cannot be the answer. Take X=100 Y=1 how can D be the Answer?



Intern
Joined: 01 Nov 2018
Posts: 30

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
03 Feb 2019, 08:56
KanishkM wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) IMO D Just test values, Given x > y If x and y are nonzero numbers Test values : 2> 1 or 1 > 2 A) \(\frac{1}{x} < \frac{1}{y}\), To avoid any confusion, always do this. \(\frac{1}{y} > \frac{1}{x}\), this works for me C1: 1 > 0.5, Yes C2: 1 > 0.5 No B) \(\frac{x}{y} > 1\) C1: 2 > 1 Yes C2: 0.5 > 1 No C) \(x > y\) This will give multiple values D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\), same here as well \(\frac{1}{x^2y} > \frac{1}{xy^2}\) For any set of values, Here i am always getting a No. E) \(\frac{x}{y} < \frac{y}{x}\) , same here as well \(\frac{y}{x} > \frac{x}{y}\)[/quote] Here you can get a Yes and a No[/quote] In A you haven't done it correct. It should be 0.5>1 after reciprocal which is a yes. Also in D, it can be proven wrong if we take 5 & 5



NUS School Moderator
Joined: 18 Jul 2018
Posts: 1020
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
03 Feb 2019, 08:59
None of the options is correct. All give Yes or No as answers.
_________________
Press +1 Kudos If my post helps!



Manager
Joined: 02 Jan 2017
Posts: 59
Location: India

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
03 Feb 2019, 09:01
Afc0892 wrote: AlN wrote: 4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) Can someone tell me why C is wrong If you take x as 2 and y as 3. We can see that x > y as 2 > 3. But x = 2 and y = 3. And x is not greater than y. Hence C is wrong Posted from my mobile deviceThank you Got it!



SVP
Joined: 03 Jun 2019
Posts: 1756
Location: India

If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
18 Aug 2019, 23:37
4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) Given: x and y are nonzero numbers such that x > y Asked: Which of the following is always true? A) \(\frac{1}{x} < \frac{1}{y}\) If xy>0 ; \(\frac{1}{x} < \frac{1}{y}\) If xy<0 ; \(\frac{1}{x} > \frac{1}{y}\) 3>2 => 1/3<1/2 YES 2>3 => 1/2<1/3 YES 3>2 => 1/3<1/2 NO NOT NECESSARILY TRUE B) \(\frac{x}{y} > 1\) If y>0 x/y >1 ; 3>2 => 3/2 > 1 YES If y<0 x/y <1 ; 3>2 => 3/2>1 NO NOT NECESSARILY TRUE C) \(x > y\) 3>2 => 3>2 YES 2>3 => 2 > 3 => 2>3 NO NOT NECESSARILY TRUE D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\) \(\frac{1}{xy^2} < \frac{1}{x^2y}\) Multiplying both sides by\(x^2y^2\) x>y TRUE MUST BE TRUE E) \(\frac{x}{y} < \frac{y}{x}\) 3>2 => 3/2 < 2/3 NO NOT NECESSARILY TRUE IMO D
_________________
"Success is not final; failure is not fatal: It is the courage to continue that counts." Please provide kudos if you like my post. Kudos encourage active discussions. My GMAT Resources:  Efficient LearningAll you need to know about GMAT quantTele: +911140396815 Mobile : +919910661622 Email : kinshook.chaturvedi@gmail.com



Math Expert
Joined: 02 Sep 2009
Posts: 58464

Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
Show Tags
18 Aug 2019, 23:58
4d wrote: If x and y are nonzero numbers such that x > y, which of the following is always true?
A) \(\frac{1}{x} < \frac{1}{y}\)
B) \(\frac{x}{y} > 1\)
C) \(x > y\)
D) \(\frac{1}{xy^2} < \frac{1}{x^2y}\)
E) \(\frac{x}{y} < \frac{y}{x}\) This is a flawed question. None of the options is always true. D cannot be the answer because it's never true if x > y. Check x = 2 and y = 1. TOPIC IS LOCKED.
_________________




Re: If x and y are nonzero numbers such that x>y, which of the following
[#permalink]
18 Aug 2019, 23:58






