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03 Jul 2022, 10:00
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
34% (02:03) correct
66%
(02:21)
wrong
based on 41
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are non-zero numbers, what is the value of y?
(1) \(4^x=\frac{64}{16^y}\)
(2) \((5x)^{−y}=25\)
(1) \(4^x=\frac{64}{16^y}\)
(2) \((5x)^{−y}=25\)
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Bunuel
Answer is (B) IMO, but the answer is (E).
From statement (1), \(4^{x}*16^{y} = 64\) can be simplified to \(x + 2y = 3\). One equation, two variables, not possible to find x & y. INSUFFICIENT.
From statement (2), \(5x^{−y}=25\) can be simplified to \(5x^{y} = 5^{-2}\). Here, x = 1, y = -2. SUFFICIENT.
Would like to know what I'm doing wrong in this question. Bunuel it would be great if you can help out.
16 Jan 2024, 03:45
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twoface07
There's an error in your reasoning in (St.2)
5x^-y=25
= (1/5x)^y=25
= (1/5x)^y=5^2
Therefore if y=1, x=0.008 or 100/12500 and can change with every changing value of y
