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If x and y are positive integers and 180x = y^3, which of the following must be an integer?

I. \(\frac{x}{(2^2*3*5)}\)

II. \(\frac{x}{(2*3^2*5)}\)

III. \(\frac{x}{(2*3*5^2)}\)


(A) None
(B) I only
(C) II only
(D) III only
(E) I and II

Solution:

Since 180x = y^3, we see that 180x must be a perfect cube. Recall that a perfect cube has prime factors whose exponents are positive multiples of 3. Let’s first factor 180:

180 = 18 x 10 = 2^2 x 3^2 x 5^1

Now, to make the expression 180x a perfect cube, we need x to contain at least one 2, at least one 3, and at least two fives. (If that happened, then 180x would be 2^3 x 3^3 x 5^3, which would make it a perfect cube.)

Since we are given that 180x is a perfect cube, the minimum value of x is 2^1 x 3^1 x 5^2, so only III MUST be an integer.

Answer: D
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If x and y are positive integers and 180x = y^3, which of the following must be an integer?

I. x(22∗3∗5)x(22∗3∗5)

II. x(2∗32∗5)x(2∗32∗5)

III. x(2∗3∗52)x(2∗3∗52)


(A) None
(B) I only
(C) II only
(D) III only
(E) I and II
I'm a noob so help me out

Considering x = 150 (since 150x180 = 27000 which is 30^3)
x = 150 only satisfies III

Considering x = 1200, (since 180x1200 = 216000 which is 60^3)
x = 1200 satisfies options options I and III both.

Am I doing something wrong?
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BlueRiceCakes

Quote:
If x and y are positive integers and 180x = y^3, which of the following must be an integer?

I. \(\frac{x}{(2^2*3*5)}\)

II. \(\frac{x}{(2*3^2*5)}\)

III. \(\frac{x}{(2*3*5^2)}\)

(A) None
(B) I only
(C) II only
(D) III only
(E) I and II­
I'm a noob so help me out

Considering x = 150 (since 150x180 = 27000 which is 30^3)
x = 150 only satisfies III

Considering x = 1200, (since 180x1200 = 216000 which is 60^3)
x = 1200 satisfies options options I and III both.

Am I doing something wrong?
­
The question asks which of the following MUST be an integer, not COULD be an integer. While all options COULD result in an integer for SOME particular values of x, only option D will be an integer for ALL valid values of x. To determine which MUST be an integer, we consider the least value of x possible.

Check similar questions to practice:
https://gmatclub.com/forum/what-is-the- ... 21070.html (GMAT Club Tests)
https://gmatclub.com/forum/what-is-the- ... 68984.html (GMAT Club Tests)
https://gmatclub.com/forum/if-n-and-y-a ... 92562.html
https://gmatclub.com/forum/if-n-is-a-po ... 29929.html
https://gmatclub.com/forum/if-p-is-a-po ... 98638.html
https://gmatclub.com/forum/if-x-is-a-po ... 88388.html
https://gmatclub.com/forum/x-is-divisib ... 06841.html
https://gmatclub.com/forum/if-x-and-y-a ... 30696.html
https://gmatclub.com/forum/if-5400mn-k- ... 09284.html
https://gmatclub.com/forum/if-m-and-n-a ... 08985.html
https://gmatclub.com/forum/if-n-and-y-a ... 92562.html

Hope it helps.­
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