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Bunuel
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Solution



Given:
• x and y are positive integers

To find:
• Whether the value of x is odd or not

Analysing Statement 1
• As per the information provided in Statement 1, \(\frac{y}{x}\) is a prime number
• This can be feasible with multiple values of x and y
    o If y = 9 and x = 3, then \(\frac{y}{x}\) = 3, a prime number and x is an odd number
    o If y = 4 and x = 2, then \(\frac{y}{x}\) = 2, a prime number and x is an even number
Hence, from Statement 1 we cannot say whether x is odd or not

Analysing Statement 2
• As per the information provided in Statement 2, x*y is prime
• If the product of x and y is prime, then one of them has to be a prime number and the other one must be 1
    o Now if we assume x = 1, y can be any prime number
    o But if we assume y = 1, x can be either even prime or odd prime
Hence, from Statement 2 we cannot say whether x is odd or not

Combining Both Statements
• Considering both the statements together, we can say
    o Product of x and y is prime
    o Ratio of y and x is prime
• We already know if \(x*y\) = prime, one of x and y must be prime
    o But if we consider the 2nd statement also, x must be equal to 1 – as any other value of x will violate the 1st condition (also x cannot be equal to y, as \(\frac{y}{x}\) will become 1, which is not a prime number)
• As we can say that x is equal to 1, x is an odd number

Hence, the correct answer is option C.

Answer: C
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Bunuel
If x and y are positive integers, is x odd?

(1) y/x is a prime number
(2) x*y is a prime number

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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We can solve this by using examples. Lets get down to statements.

Statement 1: Easiest numbers to take when a question is testing prime numbers and odd-even concept is to take 2 and 3.

If x=2 and y=6, then y/x=6/2=3 which is prime. Here, x is even

If x=3 and y=6, then y/x=6/3=2, which is prime. Here, x is odd. Clearly, this statement is insufficient.

Statement 2: For multiplication of two numbers to be prime, one of them has to necessarily be 1 and other has to be a prime number. We are already given x and y are positive integers. So, latter condition is satisfied. For the former, lets take the same cases we have taken before:

If x=2 and y=1, then xy=2 which is prime. Here, x is even

If x=3 and y=1, then xy=3, which is prime. Here, x is odd. Clearly, this statement is insufficient.

Note here: You could have taken x to be 1 in both cases, but that would really not give you a conclusive proof. Hence, we tested x to be a prime number.

Combining statements 1 & 2: The only way these two statements will be true is if x=1. This is because if x were any other positive integer, y will have to be a multiple of x, in order for statement 1 to give us a prime number. And if that was the case, xy would never be a prime number.

Let me take an example:

If x=2 and y=6, then y/x=6/2=3 which is prime. This satisfies statement 1
But, for statement 2, xy=2*6=12 which is not prime. Hence, statement 2 is not satisfied.

Thus, x has to be 1 which is odd.

Hence, correct answer is C
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