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# If x and y are positive intergers, what is the remainder

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If x and y are positive intergers, what is the remainder  [#permalink]

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19 Feb 2011, 11:13
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If x and y are positive intergers, what is the remainder when 10^x+y is divided by y?

(1) x=5
(2) y=2

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19 Feb 2011, 11:22
Baten80 wrote:
If x and y are positive intergers, what is the remainder when 10^x+y is divided by y?

(1) x=5
(2) y=2

$$\frac{10^x+y}{y}=\frac{10^x}{y}+1$$ --> so we basically need the remainder upon division 10^x by y (as in 10^x+y the second term y is divisible by y itself then only the first term matters for remainder).

(1) x=5 --> need the value of y. Not sufficient.
(2) y=2 --> as x is a positive integer then 10^x is an even number and 10^x=even divided by 2 yields the remainder of zero. Sufficient.

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Re: If x and y are positive intergers, what is the remainder  [#permalink]

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15 Aug 2013, 21:21
REM[10^(x+y)]/y

(1) x=5

REM[10^(5+y)]/y no information about y so REM is not consistent hence INSUFFICIENT.

(2) y=2

REM[10^(x+2)]/2

Any power of 10 is even => Divisible by 2 => REM =0

Hence SUFFICIENT

Hence (B) !
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Re: If x and y are positive intergers, what is the remainder  [#permalink]

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20 Jul 2018, 00:32
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Re: If x and y are positive intergers, what is the remainder &nbs [#permalink] 20 Jul 2018, 00:32
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