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If x and y are positive numbers such that x + y = 2, then which of the
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30 Jun 2018, 11:07
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Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. II only C. III only D. I and II E. II and III
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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04 Jul 2018, 03:23
Solution Given:• x and y are positive integers • x + y = 2 To find:• From the given options, which one could be the value of 300x + 200y Approach and Working: We can rewrite the given expression 300x + 200y in the following manner: • 300x + 200y = 200x + 200y + 100x = 100x + 200 (x + y) = 100x + 200*2 = 100x + 400 Now, as x is positive, 100x > 0 • Hence, 400 + 100x > 400 Only one value is more than 400 (i.e. 533) Hence, the correct answer is option C. Answer: C
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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30 Jun 2018, 15:16
300x+200y =200*(3x+2y)=200(2x+2y+x)=200(2+x)=400+200x  so the value will depend on x only
We are given that x and y are positive numbers such that x + y = 2
x will be min = 0.00..1 when y=1.99...9 x will be max = 1.99...9 when y=0.00..1
Obviously 400<400+200x<800 . Only 533 is in that range
Answer C. III only



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Re: If x and y are positive numbers such that x + y = 2, then which of the
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30 Jun 2018, 16:07
300x+200(2x) 400+100x x>0 Answer C. Greater than 400
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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30 Jun 2018, 18:55
EgmatQuantExpert wrote: Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. I only C. III only D. I and II E. II and III This question is designed based on weighted average method. This question can be solved easily following few steps. Given, 300x + 200y = \(\frac{600x + 400y}{2}\) =\(\frac{600x + 400y}{x+y}\) Now we know that weighted average value must be between 400 to 600 where x and y are their weights. 533 falls between 400 to 600. Only option match is C.



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Re: If x and y are positive numbers such that x + y = 2, then which of the
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01 Jul 2018, 12:15
both x & y are positive numbers meanwhile their sum equals to 2 Therefore, x&y could be (1,1)or (0,2) or (2,0) therefore 300x+200y= 300(1)+200(1)= 500 Or = 300(0)+200(2)= 400 Or = 300(2)+200(0)=600 Therefore, C is the correct answer, as all the answers are greater than 400
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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02 Jul 2018, 07:59
x + y = 2 => x = 2y and y = 2x
x, y are positive numbers => \(0\leq{x}\) < 2 and \(0\leq{y}\) <2
300x+200y = 300(2y)+200y = 600100y. Because \(0\leq{y}\) <2 => 600100y < 600 (1)
300x+200y = 300x+200(2x)=400+100x. Because \(0\leq{x}\) => 400 + 100x > 400 (2)
Combine (1) and (2), the answer falls between 400 and 600, hence the correct answer is 533 (Option C)



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Re: If x and y are positive numbers such that x + y = 2, then which of the
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02 Jul 2018, 09:15
NDND wrote: both x & y are positive numbers meanwhile their sum equals to 2 Therefore, x&y could be (1,1)or (0,2) or (2,0)
therefore 300x+200y= 300(1)+200(1)= 500 Or = 300(0)+200(2)= 400 Or = 300(2)+200(0)=600
Therefore, C is the correct answer, as all the answers are greater than 400 IIRC, 0 is neither positive nor negative (it is however even) so you cannot set one of the variables to 0 as the stem states that x and y are positive numbers.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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03 Jul 2018, 11:31
strivingFor800 wrote: NDND wrote: both x & y are positive numbers meanwhile their sum equals to 2 Therefore, x&y could be (1,1)or (0,2) or (2,0)
therefore 300x+200y= 300(1)+200(1)= 500 Or = 300(0)+200(2)= 400 Or = 300(2)+200(0)=600
Therefore, C is the correct answer, as all the answers are greater than 400 IIRC, 0 is neither positive nor negative (it is however even) so you cannot set one of the variables to 0 as the stem states that x and y are positive numbers. I guess you are right, which means that the only option we have is (1,1), and this would save us at least half the time, right? Thanks for correcting me
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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04 Jul 2018, 09:00
EgmatQuantExpert wrote: Solution Given:• x and y are positive integers • x + y = 2 To find:• From the given options, which one could be the value of 300x + 200y Approach and Working: We can rewrite the given expression 300x + 200y in the following manner: • 300x + 200y = 200x + 200y + 100x = 100x + 200 (x + y) = 100x + 200*2 = 100x + 400 Now, as x is positive, 100x > 0 • Hence, 400 + 100x > 400 Only one value is more than 400 (i.e. 533) Hence, the correct answer is option C. Answer: CThanks EgmatQuantExpert could you comment on the approach used on this post? https://gmatclub.com/forum/ifxandya ... l#p2088234 Is it ok? Thx
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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05 Jul 2018, 04:23
NDND wrote: Thanks EgmatQuantExpert could you comment on the approach used on this post? https://gmatclub.com/forum/ifxandya ... l#p2088234 Is it ok? Thx Hey NDND, can you specify which solution you are referring to? The link you have provided somehow reverts back to the above post only.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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05 Jul 2018, 11:29
EgmatQuantExpert wrote: NDND wrote: Thanks EgmatQuantExpert could you comment on the approach used on this post? https://gmatclub.com/forum/ifxandya ... l#p2088234 Is it ok? Thx Hey NDND, can you specify which solution you are referring to? The link you have provided somehow reverts back to the above post only. Here you go: both x & y are positive numbers meanwhile their sum equals to 2 Therefore, x&y could be (1,1)or (0,2) or (2,0) therefore 300x+200y= 300(1)+200(1)= 500 Or = 300(0)+200(2)= 400 Or = 300(2)+200(0)=600 Therefore, C is the correct answer, as all the answers are greater than 400
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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06 Jul 2018, 04:14
NDND wrote: Here you go:
both x & y are positive numbers meanwhile their sum equals to 2 Therefore, x&y could be (1,1)or (0,2) or (2,0)
therefore 300x+200y= 300(1)+200(1)= 500 Or = 300(0)+200(2)= 400 Or = 300(2)+200(0)=600
Therefore, C is the correct answer, as all the answers are greater than 400
Although the approach and final answer is absolutely correct, there is a very small error in the calculation part. In the question it was mentioned that both x and y are positive integers, hence they are always greater than 0. • Nonnegative integers (Whole Numbers) start from 0. • Positive integers (Natural Numbers) start from 1. As both x and y are positive integers, they can't be equal to 0, hence, the only possible case will be (1, 1). You have identified that also in one of your previous replies.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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23 Jul 2018, 14:03
EgmatQuantExpert wrote: Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. I onlyC. III only D. I and II E. II and III Good question, but could you adjust the answer choices to reflect different statements for A. & B.?
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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23 Jul 2018, 15:40
You don't have to solve for x&y or even suppose values.
given: that x + y = 2, to find: possible values for 300x+200y?
Solution: 300x+200y = 100x + 200(x+y) = 100x + 200(2) = 100x + 400
Since x is a +ve value, so whatever it may be, it won't reduce the value of the equation from 400 in any case
So, any solution would have 2 be more than 400, which leaves us with just Option 3!



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Re: If x and y are positive numbers such that x + y = 2, then which of the
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23 Jul 2018, 22:01
EgmatQuantExpert wrote: Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. I only C. III only D. I and II E. II and III if x+y=2, then 300x+300y=600 testing options: 1. subtracting 300x+200y=156, 100y=600156=444 y=4.44 NO, must be less than 2 2. subtracting 300x+200y=397, 100y=600397=203 y=2.03 NO, must be less than 2 subtracting 300x+200y=533, 100y=600533=67 y=.67 YES, less than 2 III only C



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Re: If x and y are positive numbers such that x + y = 2, then which of the
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23 Jul 2018, 23:34
Given, X+Y=2.................1) 300x+200Y=? Multiplying Eqn 1) with 2 , 200X+200Y=200x2=400..............2) Add another 100X to the equation derived. 300X+200Y=400+100X It is going to be greater than 400 since X is positive. Hence answer C.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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17 Dec 2018, 06:41
EgmatQuantExpert wrote: Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. I only C. III only D. I and II E. II and III Dear Moderator, Came across this question, if you see the answer choices , option A and B have the same choices , making it look awkward. Hope we can do something about it. Thank you.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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17 Dec 2018, 06:45
stne wrote: EgmatQuantExpert wrote: Question1 If x and y are positive numbers such that x + y = 2, then which of the following could be the value of 300x+200y? OptionsA. I only B. I only C. III only D. I and II E. II and III Dear Moderator, Came across this question, if you see the answer choices , option A and B have the same choices , making it look awkward. Hope we can do something about it. Thank you. _________________ Edited. Thank you.
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Re: If x and y are positive numbers such that x + y = 2, then which of the
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