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Bunuel
If x and y are prime integers and x < y, which of the following cannot be true?

A. \(x\) is even

B. \(x + y\) is odd

C. \(xy\) is even

D. \(y + xy\) is even

E. \(2x + y\) is even
Let \(x = 2\) & \(y = 3\)

(A) 2 ; Possible
(B) 2 + 3 = 5; Possible
(C) 2*3 = 6 ; Possible
(D) 2 + 2*3 = 8 ; Possible
(E) 2*2 + 3 = 7 ; Not possible

Answer must be (E)
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Bunuel
If x and y are prime integers and x < y, which of the following cannot be true?

A. \(x\) is even

B. \(x + y\) is odd

C. \(xy\) is even

D. \(y + xy\) is even

E. \(2x + y\) is even

A: x = 2 is allowed. Can be true.

B: x = 2 then add any y to get an odd sum. Can be true.

C: x = 2 then multiply by any y to get an even number. Can be true.

D: \(y*(x + 1)\) is even, let x be odd so that x + 1 is even. Can be true.

E: y is forced to be odd as y cannot be 2. Then 2x + y must be even + odd = odd. Cannot be true.

Ans: E
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We are looking for an option that CANNOT be true.

If x and y are prime numbers, and x<y:

Let’s say x = 2 and y = 3

x is even; x = 2, can be true. Eliminate A

x + y is odd; x = 2 and y = 3, can be true. Eliminate B

xy is even; if we x = 2 and it’s the only even prime, the product of xy is even, can be true. Eliminate C

y + xy is even; if x = any prime other than 2 and y is a larger prime, this would result in an odd + odd which is even, can be true. Eliminate D

E. 2x + y is even; no matter what prime we assign to x, 2x will be an even number. Then y would be a be larger prime, so even + odd can never result in an even number. CANNOT be true.

Option E
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