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21 Apr 2021, 04:45
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D
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Difficulty:
65%
(hard)
Question Stats:
57% (01:54) correct
43%
(01:35)
wrong
based on 125
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x + y is equal to
(A) 2
(B) 3
(C) 4
(D) 6
(E) 8
(A) 2
(B) 3
(C) 4
(D) 6
(E) 8
Thelegend2631
Posts: 371
21 Apr 2021, 04:52
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Bunuel
Is there any Typo here?
I didn't follow highlighted text
Posted from my mobile device
Updated on: 28 Apr 2021, 10:54
Originally posted by TarunKumar1234 on 21 Apr 2021, 05:29.
Last edited by TarunKumar1234 on 28 Apr 2021, 10:54, edited 1 time in total.
Last edited by TarunKumar1234 on 28 Apr 2021, 10:54, edited 1 time in total.
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As question is edited, I updated my solution.
If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x + y is equal to
To be divisible by 80, y=0, now the number is 653x0. Now, the new number 653x will be divisible by 8, if last 3 digits, 65x, is divisible by 8.
(A) 2 -> not possible.
(B) 3 -> not possible.
(C) 4 -> not possible.
(D) 6 -> divisible. Possible.
(E) 8 -> Not possible.
So, I think D.
If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x + y is equal to
To be divisible by 80, y=0, now the number is 653x0. Now, the new number 653x will be divisible by 8, if last 3 digits, 65x, is divisible by 8.
(A) 2 -> not possible.
(B) 3 -> not possible.
(C) 4 -> not possible.
(D) 6 -> divisible. Possible.
(E) 8 -> Not possible.
So, I think D.
