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If x is a negative integer and 2 < x^2 < 36, what is the lest possible value of |2x - 11| ?
A. 7 B. 5 C. 3 D. 1 E. 0
Bunuel Given that x is negative, 2x is negative and |2x - 11| is larger than 11... Is there an error in the question?
EDIT:
As we're asked for the least possible value, we'll start from the smallest answer and work our way up. This is an Alternative approach.
If (E) were true, than |2x + 11| = 0 meaning that 2x = -11 --> x is not a negative integer. If (D) were true, than |2x + 11| = 1 meaning that 2x = 1+11 = 12 --> x is not negative or 2x = 1 - 11 = -10 and x = -5. In this case x^2 = 25 so 2 < x^2 < 36 as required.
If x is a negative integer and 2 < x^2 < 36, what is the lest possible value of |2x + 11| ?
A. 7 B. 5 C. 3 D. 1 E. 0
Given that x is a negative integer and and 2<x^2<36 so the values the X can take that satisfy this condition are -2, -3, -4,-5 i.e 2< (-2)^2 < 36 ; similarly for others Substituting the values of -2, -3, -4 and -5 in |2x+11| The lowest number would be when |2(-5) + 11| = 1 Hence D
Re: If x is a negative integer and 2 < x^2 < 36, what is the least possibl
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04 May 2018, 17:27
So, we are given that x is negative, and that square of x is between 2 and 36. That takes us to some possible values of x, such as -2,-3,-4,-5. In order to minimize the modulus |2x+11| output, we need to maximize the negative value inside the modulus. That said, the biggest value of x inside the modulus would be -5.
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78% (00:51) correct 
