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If x is a positive integer,is \(x^2\)-1 divisible by 24?
1.x is odd
If x is odd, then x-1 and x+1 will be divisible by atleast a 2 and a 4. so \(x^2-1\), which is (x-1)(x+1) will be divisible by 2*4 or 8 at least.
Now, if any one of x-1 or x+1 is divisible by 3, answer is yes, x^2-1 is divisible by 8*3. But, if x is divisible by 3, answer is no.


2.x leaves a remainder when divided by 3
Now \(x^2-1=(x-1)(x+1)\), so if x is not divisible by 3, either x-1 or x+1 will be divisible by 3. Therefore, if x is even, the answer will be no, as both x-1 and x+1 will be odd. for example, 2, 4, or 8. Where as if x is odd, for example 7, 11 etc, answer is yes


Combined..
Statement I tells us that \(x^2\)-1 divisible by at least 8, and Statement II tells us that \(x^2\)-1 divisible by at least a 3, so \(x^2\)-1 is surely divisible by at least 8*3 or 24.
Suff

C
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Apologies ,marked Option B by mistake.The correct answer is C.
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axezcole
If x is a positive integer, is x^2 - 1 divisible by 24?

(1) x is odd
(2) x leaves a remainder when divided by 3

#1
x=1,3,5 we get variation in answers, insufficient
#2
x=4,5,7
again in sufficient
from1 & 2
x=5 issufficient
IMO C
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axezcole
If x is a positive integer, is x^2 - 1 divisible by 24?

(1) x is odd
(2) x leaves a remainder when divided by 3

x≥1 (positive integer)
x^2-1=(x+1)(x-1)
factors(24)=2^3*3

(1) insufic
x=1: 0(2)/24=div
x=3: 2(4)/24≠div

(2) insufic
x=1: 0(2)/24=div
x=2: 1(3)/24≠div

(1/2) sufic
x=1: 0(2)/24=div
x=5: 4(6)/24=div
x=7: 6(8)/24=div

Ans (C)
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Even if i take both together, won't it fail at x=1?Ideally it both will onlly true together if x>5
chetan2u
If x is a positive integer,is \(x^2\)-1 divisible by 24?
1.x is odd
If x is odd, then x-1 and x+1 will be divisible by atleast a 2 and a 4. so \(x^2-1\), which is (x-1)(x+1) will be divisible by 2*4 or 8 at least.
Now, if any one of x-1 or x+1 is divisible by 3, answer is yes, x^2-1 is divisible by 8*3. But, if x is divisible by 3, answer is no.


2.x leaves a remainder when divided by 3
Now \(x^2-1=(x-1)(x+1)\), so if x is not divisible by 3, either x-1 or x+1 will be divisible by 3. Therefore, if x is even, the answer will be no, as both x-1 and x+1 will be odd. for example, 2, 4, or 8. Where as if x is odd, for example 7, 11 etc, answer is yes


Combined..
Statement I tells us that \(x^2\)-1 divisible by at least 8, and Statement II tells us that \(x^2\)-1 divisible by at least a 3, so \(x^2\)-1 is surely divisible by at least 8*3 or 24.
Suff

C
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xyz12345678
If x is a positive integer, is x^2 - 1 divisible by 24?

(1) x is odd
(2) x leaves a remainder when divided by 3

Even if i take both together, won't it fail at x=1?Ideally it both will onlly true together if x>5

x = 1 is a valid case. It’s odd and leaves a nonzero remainder when divided by 3. So, for this case x^2 - 1 = 1 - 1 = 0, which is divisible by 24. So this case gives a YES, just like other valid x. There's no contradiction.


ZERO:

1. Zero is an INTEGER.

2. Zero is an EVEN integer.

3. Zero is neither positive nor negative (the only one of this kind)

4. Zero is divisible by EVERY integer except 0 itself (\(\frac{0}{x} = 0\), so 0 is a divisible by every number, x).

5. Zero is a multiple of EVERY integer (\(x*0 = 0\), so 0 is a multiple of any number, x)

6. Zero is NOT a prime number (neither is 1 by the way; the smallest prime number is 2).

7. Division by zero is NOT allowed: anything/0 is undefined.

8. Any non-zero number to the power of 0 equals 1 (\(x^0 = 1\))

9. \(0^0\) case is NOT tested on the GMAT.

10. If the exponent n is positive (n > 0), \(0^n = 0\).

11. If the exponent n is negative (n < 0), \(0^n\) is undefined, because \(0^{negative}=0^n=\frac{1}{0^{(-n)}} = \frac{1}{0}\), which is undefined. You CANNOT take 0 to the negative power.

12. \(0! = 1! = 1\).


Also, pure algebraic questions are no longer a part of the DS syllabus of the GMAT.

DS questions in GMAT Focus encompass various types of word problems, such as:

  • Word Problems
  • Work Problems
  • Distance Problems
  • Mixture Problems
  • Percent and Interest Problems
  • Overlapping Sets Problems
  • Statistics Problems
  • Combination and Probability Problems

While these questions may involve or necessitate knowledge of algebra, arithmetic, inequalities, etc., they will always be presented in the form of word problems. You won’t encounter pure "algebra" questions like, "Is x > y?" or "A positive integer n has two prime factors..."

Check GMAT Syllabus for Focus Edition

You can also visit the Data Sufficiency forum and filter questions by OG 2024-2025, GMAT Prep (Focus), and Data Insights Review 2024-2025 sources to see the types of questions currently tested on the GMAT.

So, you can ignore this question.

Hope it helps.­
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