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(1) a/(x + y) = 2.1, where a is a positive integer.

(2) a(x + y) = 210, where a is a positive integer.

hi..

(1) a/(x + y) = 2.1, where a is a positive integer. so \(a=(x+y)*2.1..\) since a is positive integer x+y has to be a multiple of 10.. so if x is EVEN, y has to be EVEN as ODD + even cannot be 10 sufficient

(2) a(x + y) = 210, where a is a positive integer a=10, x=2, y=19...NO a=19,x=2,y=8...Yes insuff

Re: If x is an even number, is y also an even number? [#permalink]

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31 Jul 2017, 10:03

stat2 : not suff depends on the value of a and y...

stat 1: a = 2.1 * (x+y) given a is integer,,, we shud be removing the decimal from 2.1,, hence multiply by 10 atleast... if x is even hen y has to be even,,, and x cannot be odd

Re: If x is an even number, is y also an even number? [#permalink]

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09 Aug 2017, 18:10

1) a/x+y=2.1=21/10 ie x+y=10 now x is even ie 2, 4, 6, 8 only hence y can only be 8, 6, 4, 2-even sufficient 2) a(x+y)=210=2x105 or 2x5x21 or 2x5x7x3 a can be 2 and x+y can be (105) a can be 10 and x+y can be (21) ie multiple combinations of odd even is possible-not sufficient