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If x is an integer and y = 4x + 3, which of the following cannot be a

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If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 17 Aug 2018, 11:28
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A
B
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D
E

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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 17 Aug 2018, 11:37
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Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23
4x+3 =y
This implies y will always be an odd number. This means 6 can never be a divisor of y

Imo, it is B

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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 17 Aug 2018, 11:44
Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23

Here is my approach.
x is an integer --> 4x is an even integer --> 4x+3 is an odd integer.
Odd integer can't be divisible by 6 --> y can't be divisible by 6.

Answer B.
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If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 17 Aug 2018, 11:48
Answer is B

y= 4x + 3 so it could be 3,7,11,15,19,23,27,31,35, ... so Option B cannot divide any of this numbers w/o a remainder.


Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23
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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 18 Aug 2018, 16:08
Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23



y = 4x + 3

y = 4x + 2 + 1

y = 2(x+) + 1

2(x + 1 ) = always be even and if we add 1 we get odd number finally.

An odd number can never ever be divisible by even. So , 6 is our answer.

The best answer is B.
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If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 18 Aug 2018, 17:23
Bunuel I know how to solve this question but say I was on a time crunch in the real exam and I got this question, is it okay to just guess the answer is B since it is the odd one out (i.e. it is the only even number). I doubt GMAC will make it this obvious though.



Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23
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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 20 Aug 2018, 11:19
Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23


If we plug in successive integer values for x, starting with x = 0, we see that y must be values such as 3, 7, 11, 15, 19, 23, 27, etc.

Since y cannot be even, 6 cannot be a divisor of y.

Alternate Solution:

We see that y must be an odd number since 4x + 3 = even + odd = odd. Thus, the even number 6 can never divide y.

Answer: B
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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 06 Jul 2019, 16:20
Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23


find not≠factor(y) if y=4x+3 and x=z (an integer)

y = multiple of 4 + 3 or,
y = even + odd = odd

Answer (B): the only even.
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Re: If x is an integer and y = 4x + 3, which of the following cannot be a  [#permalink]

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New post 06 Jul 2019, 23:20
Bunuel wrote:
If x is an integer and y = 4x + 3, which of the following cannot be a divisor of y?

(A) 5
(B) 6
(C) 7
(D) 9
(E) 23


x=(y-3)/4
if x is an integer, then y=7, 11, 15, 19, 23, 27...odd
only even choice is 6
B
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Re: If x is an integer and y = 4x + 3, which of the following cannot be a   [#permalink] 06 Jul 2019, 23:20
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