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19 Nov 2019, 23:43
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B
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Difficulty:
25%
(medium)
Question Stats:
77% (01:12) correct
23%
(01:55)
wrong
based on 69
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Date
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If x is an integer, is y an integer?
(1) The average of x and y is not an integer.
(2) The average of x, y, and x + 6, is y.
20 Nov 2019, 00:46
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If x is an integer, is y an integer?
(Statement1): \(\frac{(x+y)}{2}\)—not integer
—>\(\frac{( 2+1)}{2 }\)—Yes
—> \(\frac{(2+1.5)}{2}\)—No
Insufficient
(Statement2):( x+y+x+6)= 3y
2x +y+6= 3y
2x+6= 2y
x+ 3= y
—> x= y—3
In order x to be integer, y must be integer.
Sufficient
The answer is B
Posted from my mobile device
(Statement1): \(\frac{(x+y)}{2}\)—not integer
—>\(\frac{( 2+1)}{2 }\)—Yes
—> \(\frac{(2+1.5)}{2}\)—No
Insufficient
(Statement2):( x+y+x+6)= 3y
2x +y+6= 3y
2x+6= 2y
x+ 3= y
—> x= y—3
In order x to be integer, y must be integer.
Sufficient
The answer is B
Posted from my mobile device
20 Nov 2019, 01:51
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(1) The average of x and y is not an integer.
average of x and y cannot be an integer, even if y is an integer or not.......INSUFFICIENT
(2) The average of x, y, and x + 6, is y
I.E (2x+6+y)/3 = y
then y have to be the median of x, y, and x + 6.... y becomes x+3
since x is an integer, x+3 is an integer...........SUFFICIENT
OA:B
average of x and y cannot be an integer, even if y is an integer or not.......INSUFFICIENT
(2) The average of x, y, and x + 6, is y
I.E (2x+6+y)/3 = y
then y have to be the median of x, y, and x + 6.... y becomes x+3
since x is an integer, x+3 is an integer...........SUFFICIENT
OA:B
