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# If x not equal to -y, is (x-y)/(x+y) > 1

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Manager
Joined: 10 Apr 2008
Posts: 53
If x not equal to -y, is (x-y)/(x+y) > 1 [#permalink]

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19 Apr 2009, 21:19
1
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50% (01:25) correct 50% (01:25) wrong based on 0 sessions

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If x not equal to -y, is $$(x-y)/(x+y) > 1$$ ?

1) x>0
2) y<0

The answer explanation uses "number picking" to solve. Is there another way?

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Last edited by thinkblue on 19 Apr 2009, 21:35, edited 1 time in total.
Senior Manager
Joined: 01 Mar 2009
Posts: 362
Location: PDX
Re: Q128 OG 11th Ed [#permalink]

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19 Apr 2009, 21:24
If (x-y)/(x+y) > 1 Then

x-y > x+y
=> 2y>0 or y>0

From B You have y<0 which answers the question. I haven't looked at the answer but is this correct ?

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Manager
Joined: 10 Apr 2008
Posts: 53
Re: Q128 OG 11th Ed [#permalink]

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19 Apr 2009, 21:37
pbanavara wrote:
If (x-y)/(x+y) > 1 Then

x-y > x+y
=> 2y>0 or y>0

From B You have y<0 which answers the question. I haven't looked at the answer but is this correct ?

Nope that's not it. You have to consider (x+y) could be negative. In which case the inequality changes - not completely sure how.
Even after I did that I didn't get the answer though
Intern
Joined: 13 Apr 2009
Posts: 12
Re: Q139 OG 11th Ed [#permalink]

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20 Apr 2009, 05:40
so what is the right answer?

I think it is E
Intern
Joined: 18 Feb 2009
Posts: 5
Re: Q139 OG 11th Ed [#permalink]

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20 Apr 2009, 07:02
even I got E.. but again by number picking.

For S1.. X>0
Case 1: x=4 y=8 Fraction = -1/3 i.e. <1

Case 2: x=4 y=-6 Fraction = -5 <1

Case 3: x=4 y=-2 Fraction = 3 > 1

For S2.. y< 0
Cas2 and Case 3 proves that S2 is not sufficient

Case 1 & Case 2 also proves that S1 and S2 together are also not sufficient.

But will be good to know if this can be done without number picking ... more than individual signs of X and Y, sign of (X+Y) is more vital.

Thanks
Akshay
Manager
Joined: 22 Feb 2009
Posts: 134
Schools: Kellogg (R1 Dinged),Cornell (R2), Emory(Interview Scheduled), IESE (R1 Interviewed), ISB (Interviewed), LBS (R2), Vanderbilt (R3 Interviewed)
Re: Q139 OG 11th Ed [#permalink]

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20 Apr 2009, 12:27
1
KUDOS
Is x-y/x+y>1 ?
or we can say is
=> (x-y/x+y)-1>0
=> -2y/x+y >0
=> 2y/x+y<0?

St 1: x>0
Not sufficient to tell whether 2y/x+y < 0

St 2: 2) y<0

Not sufficient to tell whether 2y/x+y < 0

Combining also we cannot say 2y/x+y < 0, therefore E
Intern
Joined: 14 Apr 2009
Posts: 4
Re: Q139 OG 11th Ed [#permalink]

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21 Apr 2009, 15:24
bandit wrote:
Is x-y/x+y>1 ?
or we can say is
=> (x-y/x+y)-1>0
=> -2y/x+y >0
=> 2y/x+y<0?

St 1: x>0
Not sufficient to tell whether 2y/x+y < 0

St 2: 2) y<0

Not sufficient to tell whether 2y/x+y < 0

Combining also we cannot say 2y/x+y < 0, therefore E

@bandit : Great technique to look at the equation whether it is less than or equal to zero.
But, When we combine then, then we need to use the numbers to confirm that the answer is truly E.
Manager
Joined: 19 Aug 2006
Posts: 232
Re: Q139 OG 11th Ed [#permalink]

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22 Apr 2009, 21:22
I could not see how to solve it other than by picking numbers.
However, I got E.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Q139 OG 11th Ed   [#permalink] 22 Apr 2009, 21:22
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# If x not equal to -y, is (x-y)/(x+y) > 1

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