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Bunuel
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Hello,
x + y > 1 and y - x < 3
from 1st equation
x>1-y
from 2nd equation
x>y-3
taking 1&2
we get 2x>-2
x>-1
Option 2 is must be true
Option B is correct
as Option 2 is only in option B
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Yes Krunaal seems like an oversight on my part.
Krunaal
When you substitute x > -1 in (i), x can take the value of 0, in that case y > 1

Hence, only x > -1 must be true.

Answer B.

Whoisdmx15
Given:
x + y > 1 (i) and y - x < 3(ii)

y - x < 3 => x-y>-3(iii)

(i)+(iii)
2x>-2 => x>-1

Now in (i)
(>-1)+y>1=> y>2

Hence IMO D
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Bunuel
If x + y > 1 and y - x < 3, which of the following must be true?

I. x < -1
II. x > -1
III. y > 2

(A) I only
(B) II only
(C) III only
(D) I and III
(E) None
x + y > 1
y - x < 3 ------> multiply throughout with (-1): -y + x > -3
Add the first inequality to this:

x + y > 1
x - y > -3
Adding (we can add ONLY because both are now of the same nature, i.e. "greater than"): 2x > -2 => x > -1

We cannot determine a specific range for y since we cannot eliminate x from the above inequalities

Ans B
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Can even be derived from graph by plotting both the inequalities.

As can be seen, overlapping area starts at x=-1 and is valid for all values greater than -1.

IMO: B
Attachments

line overlap.jpg
line overlap.jpg [ 154.51 KiB | Viewed 2197 times ]

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y > 1 - x
y < 3+ x

it follows that 1 - x < 3 + x and thus -2 < 2x. We can then conclude that x > -1. Thus I is false and II is true. The correct answer must be B.


Bunuel
If x + y > 1 and y - x < 3, which of the following must be true?

I. x < -1
II. x > -1
III. y > 2

(A) I only
(B) II only
(C) III only
(D) I and III
(E) None


­
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x+y > 1
x> 1-y

y-x<3
x-y>-3
x>-3+y

add both equation

2x> 1-y-3+y
2x> -2
x>-1

only option B
Bunuel
If x + y > 1 and y - x < 3, which of the following must be true?

I. x < -1
II. x > -1
III. y > 2

(A) I only
(B) II only
(C) III only
(D) I and III
(E) None


­
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