Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
23 Sep 2024, 06:24
Kudos
Bookmarks
sarthak1701
"MUST BE TRUE" ("ALWAYS TRUE"/"IS TRUE") questions:
- These questions ask which statement is always true for every valid set of numbers. If you can find just one valid set of numbers where a statement is not true, it means the statement is not always true and therefore not the correct answer. So, for 'MUST BE TRUE' questions, the plug-in method is good for eliminating an option, but it does not provide a 100% guarantee that an option is always true. For "MUST BE TRUE" questions, when using the plug-in method, if you find that more than one option appears to be correct for a particular number or set of numbers, try using different numbers to double-check. Reevaluate only those options that were previously considered correct.
"COULD BE TRUE" questions:
- The questions that ask which of the following statements could be true are different. If you can demonstrate that a statement is true for a specific set of numbers, it implies that the statement could be true and therefore is a correct answer.
You can practice more questions of this type HERE.
Hope it helps.
11 Nov 2024, 06:31
Kudos
Bookmarks
Solution:
We start by inferring from the question stem, which states that X > Y^2 > Z^4. This implies:
• X must be greater than Y^2, and Y^2 must be greater than Z^4, X > 0 , Y^2 > 0
• Since squares and fourth powers of numbers between 0 and 1 are smaller than the original numbers, we should consider values for Y and Z that are between 0 and 1 for some cases to verify each statement.
Checking Each Statement:
1. Statement I: X > Y > Z
values: X = 2, Y = 1, Z = 0
Check X > Y^2 > Z^4:
so 2 > 1 > 0, which satisfies X > Y^2 > Z^4.
Conclusion: Statement I could be true.
2. Statement II: Z > Y > X
Values: X = 1/4, Y = 1/3, Z = 1/2
Check X > Y^2 > Z^4:
Y^2 = (1/3)^2 = 1/9 and Z^4 = (1/2)^4 = 1/16, so 1/4 > 1/9 > 1/16, which satisfies X > Y^2 > Z^4.
Check Z > Y > X:
1/2 > 1/3 > 1/4, which holds.
Conclusion: Statement II could be true.
3. Statement III: X > Z > Y
Values: X = 1, Z = 1/3, Y = 1/4
Check X > Y^2 > Z^4:
Y^2 = (1/4)^2 = 1/16 and Z^4 = (1/3)^4 = 1/81, so 1 > 1/16 > 1/81, which satisfies X > Y^2 > Z^4.
Check X > Z > Y:
1 > 1/3 > 1/4, which holds.
Conclusion: Statement III could be true.
Final Conclusion: Answer: E
We start by inferring from the question stem, which states that X > Y^2 > Z^4. This implies:
• X must be greater than Y^2, and Y^2 must be greater than Z^4, X > 0 , Y^2 > 0
• Since squares and fourth powers of numbers between 0 and 1 are smaller than the original numbers, we should consider values for Y and Z that are between 0 and 1 for some cases to verify each statement.
Checking Each Statement:
1. Statement I: X > Y > Z
values: X = 2, Y = 1, Z = 0
Check X > Y^2 > Z^4:
so 2 > 1 > 0, which satisfies X > Y^2 > Z^4.
Conclusion: Statement I could be true.
2. Statement II: Z > Y > X
Values: X = 1/4, Y = 1/3, Z = 1/2
Check X > Y^2 > Z^4:
Y^2 = (1/3)^2 = 1/9 and Z^4 = (1/2)^4 = 1/16, so 1/4 > 1/9 > 1/16, which satisfies X > Y^2 > Z^4.
Check Z > Y > X:
1/2 > 1/3 > 1/4, which holds.
Conclusion: Statement II could be true.
3. Statement III: X > Z > Y
Values: X = 1, Z = 1/3, Y = 1/4
Check X > Y^2 > Z^4:
Y^2 = (1/4)^2 = 1/16 and Z^4 = (1/3)^4 = 1/81, so 1 > 1/16 > 1/81, which satisfies X > Y^2 > Z^4.
Check X > Z > Y:
1 > 1/3 > 1/4, which holds.
Conclusion: Statement III could be true.
Final Conclusion: Answer: E
04 Apr 2025, 00:06
Kudos
Bookmarks
Thank you for very nice explanations:
my doubt is in case 3:
III. x>z>y
in order to make this condition true we are assuming y>y^2,
can we also make the same condition true by assuming y<y^2 ?
my doubt is in case 3:
III. x>z>y
in order to make this condition true we are assuming y>y^2,
can we also make the same condition true by assuming y<y^2 ?
