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If x, y, and z are numbers, is z = 18 ?
[#permalink]
04 Feb 2014, 01:52
04 Feb 2014, 01:52
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If x, y, and z are numbers, is z = 18 ?
(1) The average (arithmetic mean) of x, y, and z is 6.
(2) x = -y
(1) The average (arithmetic mean) of x, y, and z is 6.
(2) x = -y
Re: If x, y, and z are numbers, is z = 18 ?
[#permalink]
04 Feb 2014, 01:52
04 Feb 2014, 01:52
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SOLUTION
If x, y, and z are numbers, is z = 18 ?
(1) The average (arithmetic mean) of x, y, and z is 6 --> x + y + z = 6*3 = 18. We cannot say whether z = 18. Not sufficient.
(2) x = -y --> x + y = 0. Clearly insufficient.
(1)+(2) x + y + z = 18 --> 0 + z = 18 --> z = 18. Sufficient.
Answer: C.
If x, y, and z are numbers, is z = 18 ?
(1) The average (arithmetic mean) of x, y, and z is 6 --> x + y + z = 6*3 = 18. We cannot say whether z = 18. Not sufficient.
(2) x = -y --> x + y = 0. Clearly insufficient.
(1)+(2) x + y + z = 18 --> 0 + z = 18 --> z = 18. Sufficient.
Answer: C.
Re: If x, y, and z are numbers, is z = 18 ?
[#permalink]
04 Feb 2014, 04:38
04 Feb 2014, 04:38
Ans. C
From S1: x+y+z=18.Not sufficient
From S2: x+y=0.Not sufficent to determine z
Combining the two we get z=18 definitely.Both are together sufficient.
From S1: x+y+z=18.Not sufficient
From S2: x+y=0.Not sufficent to determine z
Combining the two we get z=18 definitely.Both are together sufficient.
