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If √x=y, which of the following co

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If √x=y, which of the following co  [#permalink]

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New post 24 May 2017, 12:06
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Q.

If \(\sqrt{x}=y,\) which of the following could be equal to \(\frac{1}{(x^{−2})^{−2}}\)


Answer Choices

A. \(y^{-8}\)
B. \(y^{-4}\)
C. \(y^{-2}\)
D. \(y\)
E. \(y^2\)


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Re: If √x=y, which of the following co  [#permalink]

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New post 24 May 2017, 12:07
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Re: If √x=y, which of the following co  [#permalink]

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New post 24 May 2017, 13:09
\(\sqrt{x}\) = y --- we can now square both side

\(x = y^2\) --- square two more times on both sides

\(x^4 = y^8\)

\(\frac{1}{(x^{−2})^{−2}}\) = \(\frac{1}{x^{4}}\) = \(\frac{1}{y^{8}}\) = \(y^{-8}\)


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If √x=y, which of the following co  [#permalink]

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New post 24 May 2017, 22:28
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EgmatQuantExpert wrote:
Q.

If \(\sqrt{x}=y,\) which of the following could be equal to \(\frac{1}{(x^{−2})^{−2}}\)


Answer Choices

A. \(y^{-8}\)
B. \(y^{-4}\)
C. \(y^{-2}\)
D. \(y\)
E. \(y^2\)


Thanks,
Saquib
Quant Expert
e-GMAT


\(\sqrt{x}=y,\)
Squaring both sides; x = \(y^2\)

\(\frac{1}{(x^{−2})^{−2}}\) = \(\frac{1}{(x^{4})}\)

Putting value of x in the fraction; \(\frac{1}{(x^{4})}\)

\(\frac{1}{(y^2)^{4}}\) = \(\frac{1}{y^{8}}\) = \(y^{-8}\)
Answer A...
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Re: If √x=y, which of the following co  [#permalink]

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New post 31 May 2017, 06:52

Official Solution



Given:

    • \(\sqrt{x}=y\)

Working Out:

    • \(\frac{1}{(x^{−2})^{−2}}\)

    • \(\frac{1}{x^4}\)

It is given that

    • \(\sqrt{x}=y\)

Taking 8th power on both sides we get:

    • \(x^4 = y^8\)

Therefore,

    • \(\frac{1}{x^4} =\frac{1}{y^8} =y^{-8}\)

Correct Answer: Option A


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If √x=y, which of the following co  [#permalink]

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New post 04 Jun 2017, 09:01
EgmatQuantExpert wrote:
Q.
If \(\sqrt{x}=y,\) which of the following could be equal to \(\frac{1}{(x^{−2})^{−2}}\)

Answer Choices

A. \(y^{-8}\)
B. \(y^{-4}\)
C. \(y^{-2}\)
D. \(y\)
E. \(y^2\)

Thanks,
Saquib

Pick nice numbers, and y is positive. When the principal square root symbol is written in the problem, we need to consider the positive square root only.

\(\sqrt{x}=y\), and \(\sqrt{4}= 2\), so x = 4 and y = 2

\(\frac{1}{(x^{−2})^{−2}}\) = \(\frac{1}{x^4}\) ---> substitute 4 for x

= \(\frac{1}{4^4}\)

= \(\frac{1}{(2^{2})^{4}}\)

= \(\frac{1}{2^8}\)

= \(2^{-8}\)

Substitute y for 2 ---> \(y^{-8}\)

Answer A

Shorten the math: \(\frac{1}{4^4}\) = \(\frac{1}{256}\), and \(\frac{1}{256}\) = \(\frac{1}{2^8}\), which is \(2^{-8}\). Substitute y for 2 ---> \(y^{-8}\)
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If √x=y, which of the following co  [#permalink]

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New post 04 Jun 2017, 09:44
EgmatQuantExpert wrote:
Q.

If \(\sqrt{x}=y,\) which of the following could be equal to \(\frac{1}{(x^{−2})^{−2}}\)

A. \(y^{-8}\)
B. \(y^{-4}\)
C. \(y^{-2}\)
D. \(y\)
E. \(y^2\)


\(\sqrt{x}=y,\)

Or, \(x = y^2\)

Quote:
which of the following could be equal to \(\frac{1}{(x^{−2})^{−2}}\)


\(\frac{1}{(x^{−2})^{−2}}\)

= \(\frac{1}{(x^{−4})}\)

= \(x^4\)

= \(y^{2*4}\)

= \(y^{8}\)


Hence, answer will be (A) \(y^{8}\)
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Re: If √x=y, which of the following co  [#permalink]

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New post 10 Jun 2017, 06:52
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I consider it very easy EGMAT is rarely kind for students
Answer:A
Time consumed:0:50(I cross check since was in doubt of EGMAT kindness)
√x=y
x^1/2=y
we have to make it x^4
So x^1/2*8=y^8
Multiply both sides with 8
Sp,
X^4=y^8
Since
1/(x^-2)^-2
1/x^4
put equivalent of x^4
it is
1/y^8
which is
y^-8
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Re: If √x=y, which of the following co  [#permalink]

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New post 14 Feb 2019, 20:26
I still don't get the relation between both statements, could someone please help me here?

Kind regards!
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Re: If √x=y, which of the following co   [#permalink] 14 Feb 2019, 20:26
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