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mojorising800
Joined: 11 Dec 2009
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Status:Its Wow or Never
Location: India
Concentration: Technology, Strategy
Schools: Tepper '14 Goizueta '14 ISB Tippie Kelley '14 Georgia Tech Mays Katz Kenan-Flagler '14 Schulich Smith '15
GMAT 1: 670 Q47 V35
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Schools: Tepper '14 Goizueta '14 ISB Tippie Kelley '14 Georgia Tech Mays Katz Kenan-Flagler '14 Schulich Smith '15
GMAT 2: 710 Q48 V40
Posts: 111
09 Jun 2010, 12:01
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (01:45) correct
27%
(01:45)
wrong
based on 984
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If (x + y)/z > 0, is x < 0?
(1) x < y
(2) z < 0
(1) x < y
(2) z < 0
Solving this question helps.
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09 Jun 2010, 13:09
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mojorising800
If (x + y)/z> 0, is x < 0?
Note that: \(\frac{x+y}{z}>0\) means that \(x+y\) and \(z\) have the same sign - either both positive or both negative.
(1) x < y. No info about z. Not sufficient.
(2) z < 0. No info about y. Not sufficient.
(1)+(2) \(z<0\) means \(x+y<0\). Sum \(x+y<0\) and \(x<y\) (from 1): \(x+y+x<y\) --> \(2x<0\) --> \(x<0\). Sufficient.
Answer: C.
Hope it helps.
General Discussion
17 Jun 2018, 20:07
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mojorising800
x < y
Since we don’t know anything about z, statement one alone is not sufficient to answer the question.
Statement Two Alone:
z < 0
Since we don’t know anything about x and y, statement two alone is not sufficient to answer the question.
Statements One and Two Together:
Since (x+y)/z is positive and z is negative, (x + y) must be negative also. Since x < y, the only way (x + y) is negative is if x is also negative.
Answer: C
