Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
28 Mar 2012, 01:24
1
1
y-x is >5. y is odd and x is even then y-x will be odd. Lowest possible value of y-x is 7. For lowest possible value of z-x, y and z should be close, it means y and z are consecutive odd integers or z = y + 2. Hence z-x = y + 2 - x = 7 + 2 = 9.
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
28 Mar 2012, 01:26
2
1
eybrj2 wrote:
If x < y < z and y-x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
A. 6 B. 7 C. 8 D. 9 E. 10
We want to minimize \(z-x\), so we need to maximize \(x\).
Say \(z=11=odd\), then max value of \(y\) will be 9 (as \(y\) is also odd). Now, since \(y-5>x\) --> \(9-5>x\) --> \(4>x\), then max value of \(x\) is 2 (as \(x\) is even).
Hence, the least possible value of \(z-x\) is 11-2=9.
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
19 Dec 2012, 00:27
I did it like this and i am getting 7 as the answer. Kindly tell me where i went wrong.
Given x<y<z y-x>5
From the first equation i subtracted x so 0<y-x<z-x From the second equation multiply by (-1) so -y+x<-5 adding the above 2 i got 0<z-x-5 ie z-x>5 We now that z-x is odd so the next odd number is 7.
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
19 Dec 2012, 02:54
maddyboiler wrote:
I did it like this and i am getting 7 as the answer. Kindly tell me where i went wrong.
Given x<y<z y-x>5
From the first equation i subtracted x so 0<y-x<z-x From the second equation multiply by (-1) so -y+x<-5 adding the above 2 i got 0<z-x-5 ie z-x>5 We now that z-x is odd so the next odd number is 7.
You got z-x>5 but we also have y-x>5, so the least value of y-x is 7 and since z>y then the least value of z-x is 9.
_________________
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
20 Dec 2012, 11:30
We have: 1) x<y<z 2) y-x>5 3) x=2k (x is an even number) 4) y=2n+1 (y is an odd number) 5) z=2p+1 (z is an odd number) 6) z-x=? least value
z-x=2p+1-2k=2p-2k+1=2(p-k)+1 - that means that z-x must be an ODD number. We can eliminate answer choices A, C and E we are asked to find the least value, so we have to pick the least numbers since y is odd and x is even, y-x must be odd. since y-x>5, the least value for y-x must be 7, the least value for x must be 2, and, thus, the least possible value for y must be 9 (y-2=7, y=9) 2<9<z, since z is odd, the least possible value for z is 11 z-x=11-2=9
If x < y < z and y - x > 5, where x is an even integer and y and
[#permalink]
Show Tags
23 Apr 2013, 06:33
Acer86 wrote:
If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z – x ? (A) 6 (B) 7 (C) 8 (D) 9 (E) 10
The answer i am getting is 7..thought original answer is something else...can someone help me out
Question asks least possible value, thus we can substitute by least possible numbers to get to answer
A, C and E are out since they are even
Left with B and E
y-x>5 which means least value of y-x=7 (since y is odd and x is even, result will be odd) Work back: y= 5 (least value) x= -2 (least value). thus y-x = 5 - (-2) = 7 (least possible odd integer greater than 5)
Since z> y, thus least possible value of z = 7 Therefore, z-x = 7 - (-2) = 9
Correct choice D
_________________
"When the going gets tough, the tough gets going!"
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
28 Mar 2014, 00:46
ACE are out as they are even. z = odd and x is even therefore Z-X is odd. out of B or D we need to see that we have to get the minimum value of z-x so we have to minimize z and maximize x. Hence z-x is 9
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
02 Jun 2017, 08:07
1
1
eybrj2 wrote:
If x < y < z and y-x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
A. 6 B. 7 C. 8 D. 9 E. 10
Think about it this way: x < y < z Difference between y and x is more than 5 so it is at least 6. But x is even and y is odd so their difference would be odd. Hence the diff between them will be at least 7. Now z is greater than y by at least 2 (since z is odd too), hence diff between x and z is at least 9.
Answer (D)
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >
GMAT self-study has never been more personalized or more fun. Try ORION Free!
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
02 Jun 2017, 10:38
Since y-x>5; let us assume x to be -4 (even no); such that we get the least value of y. Hence y has to be either 1 or 3, but since y=1 give y-x=5, this. Ant be right. Thus we can conclude y to be 3 Therefore next available odd integer is z=5 Z-x = 5-(-4)=9
Re: If x < y < z and y-x > 5, where x is an even integer and y
[#permalink]
Show Tags
23 Oct 2017, 04:11
Easy one. Not sure if it is a 700 level question. Given x < y < z and y-x > 5 and x is even and y&z are odd. y-x>5. Now y is odd and x is even, therefore, Y can be 7, 9, 11.... and x is even and can be 0,2,4... let us plug in a set of values 7-0>5 9-0>5 9-2>5 One more condition mentioned is z>y and is odd therefore z can be 9, 11, 13.... we now have 0<7<9 and z-x=9-0=9 2<9<11 and z-x=11-2=9 Answer D
gmatclubot
Re: If x < y < z and y-x > 5, where x is an even integer and y &nbs
[#permalink]
23 Oct 2017, 04:11
close
60% (01:49) correct 
