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06 Apr 2026, 19:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
64% (01:38) correct
36%
(01:15)
wrong
based on 100
sessions
History
Date
Time
Result
Not Attempted Yet
If x > y > z, which of the following may be true?
I. x^4 > y^4 > z^4
II. z^4 > y^4 > x^4
III. y^4 > x^4 > z^4
A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III
I. x^4 > y^4 > z^4
II. z^4 > y^4 > x^4
III. y^4 > x^4 > z^4
A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III
BongBideshini
Joined: 25 May 2021
Last visit: 10 May 2026
Posts: 199
Given Kudos: 82
Location: India
Concentration: Entrepreneurship, Marketing
Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27
GPA: 3.8
WE:Engineering (Government)
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06 Apr 2026, 22:39
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Using numbers to prove the relation
1. 4>3>2
so, x^4 > y^4 > z^4 is satisfying
2. -1>-2>-3
So, z^4 > y^4 > x^4 is satisfying.
3. This is a bit tricky.
1>-2>-3
>no, y^4 > x^4 > z^4 does not hold
-1/4>-1/2>-1
> not satifying
If we try other combinations also, it does not satisfy
So, Answer (C), IMO
1. 4>3>2
so, x^4 > y^4 > z^4 is satisfying
2. -1>-2>-3
So, z^4 > y^4 > x^4 is satisfying.
3. This is a bit tricky.
1>-2>-3
>no, y^4 > x^4 > z^4 does not hold
-1/4>-1/2>-1
> not satifying
If we try other combinations also, it does not satisfy
So, Answer (C), IMO
ExpertsGlobal5
06 Apr 2026, 23:58
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You are given a relation. Now the reverse relation is possible as you can have negative values. But can you have y^4 the highest?
If you have negative y and z then magnitude when squaring would push z>y and if it is positive then x>y. Thus not possible.
Only 1 and 2 are thus possible.
Answer: Option C
If you have negative y and z then magnitude when squaring would push z>y and if it is positive then x>y. Thus not possible.
Only 1 and 2 are thus possible.
Answer: Option C
ExpertsGlobal5
