Jul 21 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes Jul 26 08:00 AM PDT  09:00 AM PDT The Competition Continues  Game of Timers is a teambased competition based on solving GMAT questions to win epic prizes! Starting July 1st, compete to win prep materials while studying for GMAT! Registration is Open! Ends July 26th Jul 27 07:00 AM PDT  09:00 AM PDT Learn reading strategies that can help even nonvoracious reader to master GMAT RC
Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 15 Feb 2012
Posts: 30

If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
11 Jul 2012, 14:05
Question Stats:
66% (01:39) correct 34% (01:31) wrong based on 324 sessions
HideShow timer Statistics
If \(\sqrt{xy} = xy\) what is the value of x + y? (1) x = 1/2 (2) y is not equal to zero What i did was, (XY)^1/2 = XY XY =(XY)^2 so, I cancelled out XY and finally I got the below rephrased equation XY=1. BUT in the MGMAT explanation, I found that they are not cancelling out XY. Below is their rephrased equation. XY = (XY)^2 XY(XY)^2=0 XY [1(XY)] = 0 so, XY = 0 or XY = 1. My question is why we are not cancelling out, and when we should use cancelling technique.
Official Answer and Stats are available only to registered users. Register/ Login.




Math Expert
Joined: 02 Sep 2009
Posts: 56307

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
11 Jul 2012, 14:22
If \(\sqrt{xy} = xy\) what is the value of x + y? \(\sqrt{xy} = xy\) > \(xy=x^2y^2\) > \(x^2y^2xy=0\) > \(xy(xy1)=0\) > either \(xy=0\) or \(xy=1\). (1) x = 1/2 > either \(\frac{1}{2}*y=0\) > \(y=0\) and \(x+y=\frac{1}{2}\) OR \(\frac{1}{2}*y=1\) > \(y=2\) and \(x+y=\frac{5}{2}\). Not sufficient. (2) y is not equal to zero. Clearly not sufficient. (1)+(2) Since from (2) \(y\neq{0}\), then from (1) \(y=2\) and \(x+y=\frac{5}{2}\). Sufficient. Answer: C. As for your solution: you cannot divide by \(xy\) since \(xy\) could equal to zero and division by zero is not allowed. Never reduce equation by variable (or expression with variable), if you are not certain that variable (or expression with variable) doesn't equal to zero. We can not divide by zero. So, if you divide (reduce) by \(xy\) you assume, with no ground for it, that \(xy\) does not equal to zero thus exclude a possible solution. Hope it's clear.
_________________




Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9449
Location: Pune, India

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
11 Jul 2012, 22:57
Responding to a pm: "If \(\sqrt{XY} = XY\) what is the value of x + y?
(1) x = 1/2 (2) y is not equal to zero
What i did was,
(XY)^1/2 = XY XY =(XY)^2
so, I cancelled out XY and finally I got the below rephrased equation
XY=1.
BUT in the MGMAT explanation, I found that they are not cancelling out XY.
Below is their rephrased equation.
XY = (XY)^2
XY(XY)^2=0
XY [1(XY)] = 0
so, XY = 0 or XY = 1.
My question is why we are not cancelling out and when we should use cancelling technique."For the time being, forget this question. Look at another one. Which values of x satisfy this equation: \(x^2 = x\) Let's say we cancel out x from both sides. What do we get? x = 1. So we get that x can take the value 1. But is your answer complete? I look at the equation and I say, 'x can also take the value 0.' Am I wrong? No. x = 0 also satisfies your equation. So why didn't you get it using algebra? It is because you canceled x. Let me treat this equation differently now. \(x^2 = x\) \(x^2  x = 0\) \(x * (x  1) = 0\) x = 0 OR (x  1) = 0 i.e. x = 1 Now I get both the possible values that x can take. I do not lose a solution. When you cancel off a variable from both sides of the equation, you lose a solution so you should not do that. You can cancel off constants of course. Rule of thumb: Do not cancel off variables. Take them common. In some cases, it may not matter even if you do cancel off but either ways, your answer will not be incorrect of you don't cancel. On the other hand, sometimes, your solution could be incomplete if you do cancel and that's a problem.
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >



Intern
Joined: 12 Jul 2012
Posts: 21

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
12 Jul 2012, 03:00
Here is my solution
Take square of both sides: (root(xy) )^2 = (xy)^2 xy = (xy)^2 With Option (1): x = 1/2 1/2y = 1/4 * y^2 y = 4 * (1/2) y = 2 Hence, X+Y = 1/2  2 = 5/2.



Math Expert
Joined: 02 Sep 2009
Posts: 56307

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
12 Jul 2012, 03:06
RamakantPareek wrote: Here is my solution
Take square of both sides: (root(xy) )^2 = (xy)^2 xy = (xy)^2 With Option (1): x = 1/2 1/2y = 1/4 * y^2 y = 4 * (1/2) y = 2 Hence, X+Y = 1/2  2 = 5/2. There is another value of \(y\) apart 2 which satisfies \(\frac{1}{2}*y=\frac{1}{4}*y^2\), namely \(y=0\). Complete solution here: ifrootxyxywhatisthevalueofxy135646.html#p1103625
_________________



Math Expert
Joined: 02 Sep 2009
Posts: 56307

If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
15 Oct 2014, 16:01
7. Algebra For more check Ultimate GMAT Quantitative MegathreadHope it helps.
_________________



Intern
Joined: 18 Dec 2013
Posts: 25
Location: Canada
GPA: 2.84
WE: Project Management (Telecommunications)

If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
15 Oct 2014, 20:57
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0
Statement 1: \(X=1/2\).... substitute in main equation
Scenario A: \(Y = 2/1\) is a reciprocal \(\sqrt{xy}=xy\) LHS =\(\sqrt{1/2*2/1}= \sqrt{1}= 1\) RHS =\(1/2*2/1= 1*1 = 1\) Therefore, LHS = RHS
Scenario B: \(Y = 0\) LHS =\(\sqrt{1/2*0}= \sqrt{0}= 0\) RHS =\(1/2*0= 0\) Therefore again, LHS = RHS
Hence, we have two possible solutions, therefore Statement 1 is insufficient
Statement 2 : \(Y\) is not equal to zero But, X could be equal to zero or be the reciprocal of Y, therefore, statement 2 would fall under the same scenarios as statement 1
Hence, we have two possible solutions, therefore Statement 2 is insufficient
Both Statement 1 & 2 together confirms that \(X & Y\) both are not equal to zero, therefore, they have to be reciprocals and since statement gives us the value of \(X=1/2\), we can also the value of \(Y=2/1\) (Reciprocal of X) and thereafter we can find the value of \(X + Y = 1/2 + 2/1 = 5/2\)
Hence, both together are sufficient, therefore C is the correct Answer!



Manager
Joined: 21 Jul 2014
Posts: 122

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
15 Oct 2014, 21:26
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0 I did something similar to DMMK, except for one thing: I know \(\sqrt{n}\) = \(n\) only when \(n\) = 0 or \(n\) = 1. For all other values of \(n\), the two would not be equal. Knowing this made it much simpler to plug in the statements. I just had to determine if from the statement(s) provided, can I rule out xy = 0 or xy=1. Stament 1: Knowing that x = 1/2, y could equal 0 or 2, and still make the premise true. Either value of y would make x + y a different value. Therefore, it is insufficient. Statement 2: Knowing that y is not equal to 0, x could equal zero or the inverse of y, and still make the premise true. Either value of x would make x + y a different value. Therefore, it is insufficient. Now to evaluate both statements together. The reason we rejected statement 1 by itself was because y could equal one of two possible values. Statement 2 eliminates one of those options. Therefore y must equal 2. And therefore both statements together are sufficient to answer "what is the value of x+y."



Senior Manager
Joined: 13 Jun 2013
Posts: 271

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
15 Oct 2014, 22:12
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0 let xy=k, thus k^(1/2) =k; squaring both sides we have k=k^2 k(k1)=0 k=0 or 1 i.e. xy=0 or xy=1 st.1 for x=1/2 both y=0 and y=2 satisfy the possible value of xy i.e. 0 or 1 hence not sufficient st.2 y is not equal to zero. clearly not sufficient. as nothing is said about x, therefore x can take any value it can be zero, fraction, integer etc. combining st.1 and st.2 we know that y cannot be equal to zero. thus y=2 and x=1/2 and x+y= 2(1/2)=5/2 hence sufficient.



Intern
Joined: 02 Jan 2015
Posts: 31
GMAT Date: 02082015
GPA: 3.7
WE: Management Consulting (Consulting)

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
04 Jul 2015, 08:43
Why can't x and y both be 1? Thanks



Math Expert
Joined: 02 Sep 2009
Posts: 56307

Re: If root(xy) = xy what is the value of x + y?
[#permalink]
Show Tags
05 Jul 2015, 08:19
ElCorazon wrote: Why can't x and y both be 1? Thanks From the stem x = y = 1 is possible, in this case xy = 1 (check my solution above). But then the first statement says that x = 1/2, thus these values are no longer possible. Hope it's clear.
_________________



Senior Manager
Joined: 20 Aug 2015
Posts: 388
Location: India

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
16 Nov 2015, 03:02
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0 Given: √(xy) = xy (xy)^2  xy = 0 xy = 0 or 1  (i) Required: x + y = ? Statement 1: x = 1/2 From the given equation (i), we can have two different values of y. Hence two different values of x + y INSUFFICIENTStatement 2: y is not equal to 0 No information about x INSUFFICIENTCombining Statement 1 and Statement 2: x = 1/2 and y is not equal to 0 From (i), xy cannot be 0 since both x and y are not = 0 Hence xy = 1 y = 2 x + y = \(\frac{5}{2}\) SUFFICIENTOption C



Retired Moderator
Status: Long way to go!
Joined: 10 Oct 2016
Posts: 1344
Location: Viet Nam

If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
14 Apr 2017, 07:13
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0 The trick here is from \(\sqrt{xy}=xy\) anyone could easily deduce that \(xy=1\) or \(xy=0\) and just consider one of these cases. Here is my solution: \(\sqrt{xy}=xy \implies \sqrt{xy}xy=0 \implies \sqrt{xy}(\sqrt{xy}1)=0\) Hence we have \(xy=0\) or \(xy=1\). (1) If \(x=\frac{1}{2}\), we need to consider two cases: Case 1: If \(xy=0\implies y=0 \implies x+y = \frac{1}{2}\) Case 2: If \(xy=1 \implies y=2 \implies x+y = \frac{5}{2}\) It's clear that (1) is insufficient. (2) If \(y \neq 0\), we still need to consider two cases: Case 1: If \(xy=0\implies x=0 \implies x+y = y\). If \(y=1 \implies x+y = 1\) If \(y=2 \implies x+y = 2\) Hence, (2) is insufficient. Now combine (1) and (2): Since \(x \neq 0\) and \(y \neq 0\) hence \(xy \neq 0 \implies xy=1\) Since \(x= \frac{1}{2} \implies y = 2 \implies x+y = \frac{5}{2}\) Hence (1) & (2) are sufficient. The answer is C.
_________________



Director
Joined: 12 Nov 2016
Posts: 713
Location: United States
GPA: 2.66

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
10 Sep 2017, 13:41
Bunuel wrote: Tough and Tricky questions: Algebra. If √(xy) = xy, what is the value of x + y? (1) x = 1/2 (2) y is not equal to 0 rewrite xy= (xy)^2 St 1 Reciprocal property. 1/2(2) =1 [1/2(2)]^2 =1 insuff St 2 Eliminating the possibility of 0 from Y still leaves the possibility of x being 0 or some other numbers which leads to several possibilities. insuff St 1 and St 2 Eliminates possibility of y=2 C



SVP
Status: It's near  I can see.
Joined: 13 Apr 2013
Posts: 1687
Location: India
Concentration: International Business, Operations
GPA: 3.01
WE: Engineering (Real Estate)

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
27 Dec 2017, 00:35
Bunuel wrote: If \(\sqrt{xy} = xy\) what is the value of x + y?
\(\sqrt{xy} = xy\) > \(xy=x^2y^2\) > \(x^2y^2xy=0\) > \(xy(xy1)=0\) > either \(xy=0\) or \(xy=1\).
(1) x = 1/2 > either \(\frac{1}{2}*y=0\) > \(y=0\) and \(x+y=\frac{1}{2}\) OR \(\frac{1}{2}*y=1\) > \(y=2\) and \(x+y=\frac{5}{2}\). Not sufficient.
(2) y is not equal to zero. Clearly not sufficient.
(1)+(2) Since from (2) \(y\neq{0}\), then from (1) \(y=2\) and \(x+y=\frac{5}{2}\). Sufficient.
Answer: C.
As for your solution: you cannot divide by \(xy\) since \(xy\) could equal to zero and division by zero is not allowed.
Never reduce equation by variable (or expression with variable), if you are not certain that variable (or expression with variable) doesn't equal to zero. We can not divide by zero. So, if you divide (reduce) by \(xy\) you assume, with no ground for it, that \(xy\) does not equal to zero thus exclude a possible solution.
Hope it's clear. Is it safe to say : x^2 = x only when x = 0 or 1
_________________
"Do not watch clock; Do what it does. KEEP GOING."



Math Expert
Joined: 02 Sep 2009
Posts: 56307

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
27 Dec 2017, 00:39
QZ wrote: Bunuel wrote: If \(\sqrt{xy} = xy\) what is the value of x + y?
\(\sqrt{xy} = xy\) > \(xy=x^2y^2\) > \(x^2y^2xy=0\) > \(xy(xy1)=0\) > either \(xy=0\) or \(xy=1\).
(1) x = 1/2 > either \(\frac{1}{2}*y=0\) > \(y=0\) and \(x+y=\frac{1}{2}\) OR \(\frac{1}{2}*y=1\) > \(y=2\) and \(x+y=\frac{5}{2}\). Not sufficient.
(2) y is not equal to zero. Clearly not sufficient.
(1)+(2) Since from (2) \(y\neq{0}\), then from (1) \(y=2\) and \(x+y=\frac{5}{2}\). Sufficient.
Answer: C.
As for your solution: you cannot divide by \(xy\) since \(xy\) could equal to zero and division by zero is not allowed.
Never reduce equation by variable (or expression with variable), if you are not certain that variable (or expression with variable) doesn't equal to zero. We can not divide by zero. So, if you divide (reduce) by \(xy\) you assume, with no ground for it, that \(xy\) does not equal to zero thus exclude a possible solution.
Hope it's clear. Is it safe to say : x^2 = x only when x = 0 or 1 Yes. x^2 = x; x^2 x = 0; x(x  1) = 0; x = 0 or x = 1.
_________________



Intern
Joined: 30 Jul 2017
Posts: 20

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
27 Feb 2018, 10:18
Hi, why aren't we accounting for option where both x and y are equal to 1? then x+y is 2



Math Expert
Joined: 02 Sep 2009
Posts: 56307

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
27 Feb 2018, 10:27
krikre wrote: Hi, why aren't we accounting for option where both x and y are equal to 1? then x+y is 2 Doesn't (1) say that x = 1/2? How it can be 1 then?
_________________



Manager
Joined: 23 Sep 2016
Posts: 238

Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
Show Tags
28 Feb 2018, 01:19
prakash111687 wrote: If \(\sqrt{xy} = xy\) what is the value of x + y? (1) x = 1/2 (2) y is not equal to zero What i did was, (XY)^1/2 = XY XY =(XY)^2 so, I cancelled out XY and finally I got the below rephrased equation XY=1. there are various cases that are possible as following BUT in the MGMAT explanation, I found that they are not cancelling out XY. Below is their rephrased equation. XY = (XY)^2 XY(XY)^2=0 XY [1(XY)] = 0 so, XY = 0 or XY = 1. My question is why we are not cancelling out, and when we should use cancelling technique. IMO C \(\sqrt{xy} = xy\) 1.x=0 ,y = anything 2.Y=0 , x=anything 3. both x and y 1 or 1 or x=1 and y=1 or vise versa 4.x=1/z and y=z *any integer except 0 lets come to statement 1. x=1/2 y can be 2 or 0 insufficient. 2nd statement y not equal to 0 but don't know about x combining both case with 0 is eliminated only one case left so C is the answer




Re: If √(xy) = xy, what is the value of x + y?
[#permalink]
28 Feb 2018, 01:19






