Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If xyz ≠ 0, is x (y + z) = 0? (1) |y + z| = |y| + |z| (2) |x + y| = |x| + |y|

I do not have an OA

Why A? from question we know that y and z has to be of different signs. from st.1, how can we assume that y and z are of different signs? take y = 2 and z=3. => |2+3|= |2| + |3| = 5

And if y = -2 and z = -2 => |-2 -2| = |-2| + |-2| => 4 = 4 .....No

and with different signs, st1 will result in Yes. statement 1 insufficient

If xyz ≠ 0, is x (y + z) = 0? (1) |y + z| = |y| + |z| (2) |x + y| = |x| + |y|

I do not have an OA

Why A? from question we know that y and z has to be of different signs. from st.1, how can we assume that y and z are of different signs? take y = 2 and z=3. => |2+3|= |2| + |3| = 5

And if y = -2 and z = -2 => |-2 -2| = |-2| + |-2| => 4 = 4 .....No

and with different signs, st1 will result in Yes. statement 1 insufficient

IMO anwer is E

rishi haven't you proved that y and z have to be of the same sign in your solution using the statement 1 ?

that means A is just sufficient to prove that y and z are not of different signs and thus x (y + z) is NOT zero
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

If xyz ≠ 0, is x (y + z) = 0? (1) |y + z| = |y| + |z| (2) |x + y| = |x| + |y|

I do not have an OA

Why A? from question we know that y and z has to be of different signs. from st.1, how can we assume that y and z are of different signs? take y = 2 and z=3. => |2+3|= |2| + |3| = 5

And if y = -2 and z = -2 => |-2 -2| = |-2| + |-2| => 4 = 4 .....No

and with different signs, st1 will result in Yes. statement 1 insufficient

IMO anwer is E

rishi haven't you proved that y and z have to be of the same sign in your solution using the statement 1 ?

that means A is just sufficient to prove that y and z are not of different signs and thus x (y + z) is NOT zero

lol yes..silly mistake. perhaps I am thinking too much or too little.

takes a similar question.

If /x/ + /y/ = /x + y/ then which of the following must be true? (A) x + y > 0 (B) x + y < 0 (C) x - y > 0 (D) xy > 0 (E) xy < 0

ans is D... cause only thing above question suggests is that both x and y are of same digit....I got this question right and made a silly mistake in the topic question.. Gee!

If /x/ + /y/ = /x + y/ then which of the following must be true? (A) x + y > 0 (B) x + y < 0 (C) x - y > 0 (D) xy > 0 (E) xy < 0

ans is D... cause only thing above question suggests is that both x and y are of same digit....I got this question right and made a silly mistake in the topic question.. Gee!

How can we prove that for x = y = 0, D should be the answer? Somehow, I feel the question is not complete.

If /x/ + /y/ = /x + y/ then which of the following must be true? (A) x + y > 0 (B) x + y < 0 (C) x - y > 0 (D) xy > 0 (E) xy < 0

ans is D... cause only thing above question suggests is that both x and y are of same digit....I got this question right and made a silly mistake in the topic question.. Gee!

How can we prove that for x = y = 0, D should be the answer? Somehow, I feel the question is not complete.

scthakur, to me question is complete. as we discussed earlier, given equation can be right only if x and y are of same sign whether positive or negative and in both the casesxy would be > 0. here it is not that x = y = 0 but xy>0

If /x/ + /y/ = /x + y/ then which of the following must be true? (A) x + y > 0 (B) x + y < 0 (C) x - y > 0 (D) xy > 0 (E) xy < 0

ans is D... cause only thing above question suggests is that both x and y are of same digit....I got this question right and made a silly mistake in the topic question.. Gee!

How can we prove that for x = y = 0, D should be the answer? Somehow, I feel the question is not complete.

scthakur, to me question is complete. as we discussed earlier, given equation can be right only if x and y are of same sign whether positive or negative and in both the casesxy would be > 0. here it is not that x = y = 0 but xy>0

Rishi, I meant, the question shoulld also have a mention of xy <> 0. In the absence of this, D cannot be the right answer.