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If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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01 Apr 2012, 12:33
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If y = 0.jkmn, where j, k, m, and n each represent a nonzero digit of y, what is the value of y ? (1) j < k < m < n (2) j + a = k, k + a = m, and m + a = n, where j > a > 1.
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Re: Value of y [#permalink]
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01 Apr 2012, 12:56
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If y = 0.jkmn, where j, k, m, and n each represent a nonzero digit of y, what is the value of y ?(1) j < k < m < n. Many combinations are possible: 1<2<3<4, 2<3<4<5, 1<3<4<5, ... Not sufficient. (2) j + a = k, k + a = m, and m + a = n, where j > a > 1. Since \(j+a=k\) and \(j\) and \(k\) represent digits then \(a\) must be an integer. Next, since \(j > a > 1\) then the least value of \(a\) is 2 and the least value of \(j\) is 3. So, from \(j+a=k\) the least value of \(k\) is 3+2=5, from \(k + a = m\) the least value of \(m\) is 5+2=7 and from \(m + a = n\) the least value of \(n\) is 7+2=9. Now, if our initial number, \(a\), is more than 2, 3 for example, then the values of all other variables will increase and \(n\) will become more than 9, which is not possible since each variable represents a single nonzero digit. Hence: \(j=3\), \(k=5\), \(m=7\), and \(n=9\). Sufficient. Answer: B.
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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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28 May 2013, 05:28



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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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28 May 2013, 15:42
Bunuel wrote: Bumping for review and further discussion. I love the way you always able to pull numbers out of thin air and make the equation work so good



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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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16 Jan 2014, 04:36
I use this pattern: AD BCE
cross out what's incorrect.
(1) j<k<m<n > could be 1,2,3,4 or 2,3,4,5 hence IS > cross out AD
possible answers left: BCE
(2) j + a = k, k + a = m, and m + a = n, where j > a > 1
Since we're talking about units digit, every variable here is an integer. hence a is at least 2 and j at least 3. If you simplify the given expressions you get j+3a = n. If j = 3 and a = 2 we get n = 9, which is the highest possible value (0 is not an option). Hence you can calculate the other numbers. SUFFICIENT. Cross out C and E.
Left with answer B.
I basically followed the same approach as bunuel, but simplified the expressions first. Hope it's clear!



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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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11 Aug 2015, 11:24
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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11 Aug 2016, 18:45
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero [#permalink]
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18 Nov 2016, 22:41
Great Question Here y=0.jklm To get y we need j,k,l,m Statement 1 using test cases y=0.9876 y=0.8765 Clearly not sufficient Statement 2 This statement looks interesting Here j>1 and a=> (1,j) so least possible value of j is 3 a=2 => y=0.3579 Hmmm let j=4 a=2 => y=0.468[10]=> not posible as m is a single digit integer. hence the only possible value of y is 0.3579 Hence Sufficient Hence B
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Re: If y = 0.jkmn, where j, k, m, and n each represent a nonzero
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