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If y1/2 < 11/2, which of the following could be a value
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06 Aug 2012, 01:49
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Re: If y1/2 < 11/2, which of the following could be a value
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06 Aug 2012, 01:50




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Re: If y1/2 < 11/2, which of the following could be a value
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Updated on: 25 Mar 2014, 20:57
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectIf \(y\frac{1}{2} < \frac{11}{2}\), which of the following could be a value of y? (A) 11 (B) 11/2 (C) 11/2 (D) 11 (E) 22 An Easy way for this type of Problem is as follows When ever you see an in equality with modulus remember these two formulas 1.) xb < c .................This always means that ............ c+b < x < c +b 2.) xb > c ................. This always means that .......... Either x < c+b .................... or x > c+b Use this here and see.
Originally posted by mandyrhtdm on 06 Aug 2012, 18:54.
Last edited by Narenn on 25 Mar 2014, 20:57, edited 1 time in total.
Reversed the sign of 2nd inequality




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Re: If y1/2 < 11/2, which of the following could be a value
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06 Aug 2012, 08:59
well, here are 2 methods  lets just check answers,beginning with ans C 11/2 (1/2) <11/2 yes,of course, since u subtract from the number 11/2 some portion. method 2 y1/2 < 11/2 if y>1/2, then y1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6 if y<1/2, then 1/2 y<11/2 , y>6 reject it,since it contradicts with y<1/2 so, now lets check all answer choices and find the answer between 1/2 and 6 btw, do u post 700+ OG13 questions? havent seen them.
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Re: If y1/2 < 11/2, which of the following could be a value
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06 Aug 2012, 09:33
LalaB wrote: well, here are 2 methods 
lets just check answers,beginning with ans C
11/2 (1/2) <11/2 yes,of course, since u subtract from the number 11/2 some portion.
method 2
y1/2 < 11/2
if y>1/2, then y1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6
if y<1/2, then 1/2 y<11/2 , y>6 reject it,since it contradicts with y<1/2
so, now lets check all answer choices and find the answer between 1/2 and 6
btw, do u post 700+ OG13 questions? havent seen them. If y<1/2, then 1/2y<11/2 ie 1/211/2 <y, ie 5<y. so y lies between 5<y<1/2. Am I correct???
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Re: If y1/2 < 11/2, which of the following could be a value
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06 Aug 2012, 09:39
SOURH7WK, yep, u r correct. it is a typo.forgive me all my sins, or only poor computing skills ))
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Re: If y1/2 < 11/2, which of the following could be a value
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07 Aug 2012, 09:50
We have to see how far the value of y is on the number line so basically, what we have here is
The distance of y from 1/2 is< 5.5 so it could be from 5 to 6.
hence answer is C



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Re: If y1/2 < 11/2, which of the following could be a value
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10 Aug 2012, 03:09



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Re: If y1/2 < 11/2, which of the following could be a value
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14 Dec 2012, 07:53
Why is
y1/2 < 11/2 equivalent to 11/2 < y1/2 < 11/2
Why am I not seeing this and why didn´t I come up with it?



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Re: If y1/2 < 11/2, which of the following could be a value
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14 Dec 2012, 08:08



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If y1/2 < 11/2, which of the following could be a value
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16 Dec 2012, 07:15
Thanks Bunnel for such a valuable reply..and +1 for you as well
I was wondering, if the equation stands at 5<y<6, should not it be that both B & C are right.. Thanks



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Re: If y1/2 < 11/2, which of the following could be a value
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Re: If y1/2 < 11/2, which of the following could be a value
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16 Dec 2012, 09:36
The inequality becomes: 11/2 < y1/2 < +11/2
Hence, 1/2 has to be added to each inequality: 11/2 + 1/2 = 5 11/2 + 1/2 = 6
After simplifying, we get: 5< y < 6 The only option that lies between 5 and 6 is 11/2, which when simplified is 5.5
Thus, the answer has to be C.



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Re: If y1/2 < 11/2, which of the following could be a value
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18 Dec 2012, 00:56
Ans: the first case gives us y<6 and the second case gives –(y1/2)<11/2 so y >5 only option c falls in the range of 5<y<6 answer (C).
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Re: If y1/2 < 11/2, which of the following could be a value
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16 Dec 2013, 11:53
Bunuel wrote: If \(y\frac{1}{2} < \frac{11}{2}\), which of the following could be a value of y? (A) 11 (B) 11/2 (C) 11/2 (D) 11 (E) 22 Practice Questions Question: 14 Page: 154 Difficulty: 600 \(y\frac{1}{2} < \frac{11}{2}\) < basically what this is saying is, "we start at 0.5, and we CANNOT go 5.5 or more steps in either direction" which means 5 < x < 6 the only one of the options that fit the restriction is 11/2 = 5.5 ... So answer (C)



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Re: If y1/2 < 11/2, which of the following could be a value
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25 Mar 2014, 12:04
If y1/2 < 11/2
First calculate origin (y1/2)=0. Origin is +1/2.
This should be read as distance from origin 1/2 is less than 11/2 units. So there is range here.
So, on the right side of 1/2 we add 11/2 units and on the left side we minus 11/2 units
(1/211/2= 5)(1/2)(1/2+11/2 = 6)
So our answer must be in range of 5 to 6. 5<y<6
only 11/2 lies in this range. Hence answer.



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Re: If y1/2 < 11/2, which of the following could be a value
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08 May 2015, 04:56
Here's a visual solution for this question: \(y\frac{1}{2}\) represents the distance of y from the point \(\frac{1}{2}\) = 0.5 on the number line. The given inequality tells us that the distance of y from the point 0.5 is less than \(\frac{11}{2}\) (that is, 5.5) The points that are at a distance of 5.5 from 0.5 on the number line are: 5 and 6 This means, 5 < y < 6 Therefore, Option C is the correct answer.
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Re: If y1/2 < 11/2, which of the following could be a value
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11 Apr 2016, 15:35
If you are confused by the algebraic solution, then it might be easier to plug in when absolute values are involved.
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Re: If y1/2 < 11/2, which of the following could be a value
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03 May 2016, 06:55
Bunuel wrote: If \(y\frac{1}{2} < \frac{11}{2}\), which of the following could be a value of y?
(A) 11 (B) 11/2 (C) 11/2 (D) 11 (E) 22
Solution: We must solve the inequality for two cases: Case 1: (y1/2) is Positive: y – ½ < 11/2 y – ½ < 11/2 Add ½ to both sides of the equation: y < 6 Case 2: (y1/2) is Negative: y – ½ < 11/2 (y – ½) < 11/2 y + ½ < 11/2 Subtract ½ from both sides of the equation: y < 5 y > 5 So we know that y is greater than 5 and less than 6. The only answer choice that fits this criterion is answer choice C, 11/2. Answer: C
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Re: If y1/2 < 11/2, which of the following could be a value
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30 Aug 2017, 06:48
Bunuel shashankism Engr2012 Hi Experts, how much I try I can not refrain from opening the modulus and assigning +ve and ve values to expressions inside modulus. Is there any short cut approach to this , please see screenshot.
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Re: If y1/2 < 11/2, which of the following could be a value &nbs
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