Joy111
If m is positive then too y is negative so statement iii is contradicted ?
In response to the doubt (also on PM)
Joy the question is asking which must always be true
I will go thru the conditions 1 and 2 once again to help you understand the condition 3
Condition 1 says "y is -ve"
That means it is saying that "y=-m^2" is always -ve
But if m=0 then y becomes 0.
So condition 1 is not true
We rule out choices A and DCondition 2 says "m is non-negative"
That means it is saying that in "y=-m^2" m is either 0 or +ve
But it is not true, m can be -ve also
From the question stem, there is no restriction on value of m, and hence m can be any number
We rule out choices B and Esolved
Answer is CPursuing further
Codition 3: "If m is negative then y is negative."
This condition
limits the values of m
It is saying that
IF m<0 then y is always -ve
The only time when y is not -ve is when m=0
as the condition says that m is less than 0 (that is to say that m is not 0)
Hence when m is -ve (less than 0) y is -veAlways True