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# If y < x, is x^2 < y^2 ? (1) y > 0 (2) x > 0

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Re: If y < x, is x^2 < y^2 ? (1) y > 0 (2) x > 0 [#permalink]
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chetan2u wrote:
carcass wrote:
If $$y < x$$, is $$x^2 < y^2$$?

(1) y > 0
(2) x > 0

MODIFY the question stem..

is $$x^2 < y^2$$? Means is |x|<|y|? Or is $$x^2-y^2<0.....(x-y)(x+y)<0$$
Now it is given that $$y<x......x-y>0$$
So 'is $$(x-y)(x+y)<0$$ ?' becomes 'is x+y<0?'.
(a) if both x and y are positive ..NO
(b) if both x and y are negative...YES
(c) If x>0 and y<0, we will require to know the exact value of x and y to answer

(1) y > 0
Now x>y, so x>y>0..
Case (a) above....NO...Suff

(2) x > 0
So both case (a) and case (c) possible
Insuff

A

If x=1/2 and y=1/4 then statement 1 is not sufficient. No where the question mentions that x and y are integers.
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Re: If y < x, is x^2 < y^2 ? (1) y > 0 (2) x > 0 [#permalink]
PrernaTalreja wrote:
chetan2u wrote:
carcass wrote:
If $$y < x$$, is $$x^2 < y^2$$?

(1) y > 0
(2) x > 0

MODIFY the question stem..

is $$x^2 < y^2$$? Means is |x|<|y|? Or is $$x^2-y^2<0.....(x-y)(x+y)<0$$
Now it is given that $$y<x......x-y>0$$
So 'is $$(x-y)(x+y)<0$$ ?' becomes 'is x+y<0?'.
(a) if both x and y are positive ..NO
(b) if both x and y are negative...YES
(c) If x>0 and y<0, we will require to know the exact value of x and y to answer

(1) y > 0
Now x>y, so x>y>0..
Case (a) above....NO...Suff

(2) x > 0
So both case (a) and case (c) possible
Insuff

A

If x=1/2 and y=1/4 then statement 1 is not sufficient. No where the question mentions that x and y are integers.

statement I gives answer as NO always, so statement I is sufficient.
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Re: If y < x, is x^2 < y^2 ? (1) y > 0 (2) x > 0 [#permalink]
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Re: If y < x, is x^2 < y^2 ? (1) y > 0 (2) x > 0 [#permalink]
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