Given\( z = x * y^3\)
\(x \geq{1}\) ; \(y \geq{1}\)
Questiony = ?
Statement 1The number of different positive factors of z is 4.
\( z = x * y^3\)
Now y can be = 1, and x can be a cube of a prime number.
So \(x = p^3\)
\(z = p^3 * 1\)
Alternatively,
y can be any prime number and x = 1
Hence, we can
eliminate A and DStatement 2z is the product of two different prime numbers.
So, \(z = p_1 * p_2\)
Also \( z = x * y^3\)
Now there can be multiple scenarios we can think of
- y is a prime number and x is also a prime number : In that case, z is a multiple of more than two prime numbers, hence this is not a valid case.
- y is a prime number and x = 1 : In that case, z is again a multiple of more than two prime numbers, hence this is also not a valid case.
- \(x = p_1 * p_2\) and y = 1 : This is valid.
Note: We don't even have to consider scenario 1 and scenario 2 (to save time). It's given that y is an integer, so if y has any prime factors in it, z will be a product of more than two prime factors. Hence y has to be equal to 1.
Thus have a definite answer.
IMO B