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the language of the question statement is tricky.
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Hi Marty,

How are you calculating the median method?
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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To calculate median you take every data point and order it from least to greatest. You then find the middle of the ordered data set and that number is the median.

For example: 1,3,6,1,8,2,4
Ordered: 1,1,2,3,4,6,8
Median is 3 because it is the midpoint in the dataset.


In this case, take performer A for instance:

He had 51 ratings for rank 1 and 49 for rank 4.

If we ordered them all: 1,1,1,1,1,1.....4,4,4,4,4,4 the middle data point would be 1, as he received more than half rank 1 ratings.
Therefore his median ranking is 1

AditiDeokar
Hi Marty,

How are you calculating the median method?
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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One way to solve this, determine what Mode and Median rank each performer is being assigned.

Like A, Mode rank: 1 , Median Rank:1
B, Mode rank:....

You will see there is no conflict and using both systems same ranks are being assigned hence Same for all the choices.
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MartyMurray

While the answer will remain the same, by Mode method I understood that from the ranks let's say A has gotten, which one has he gotten the most times is the Mode rank. So since A got Rank 1 51 times, that is the answer. Could you please clarigy - will be helpful for other questions with similar wordings
MartyMurray
In a music contest, a panel of 100 audience members ranked each of 4 performers with integer ranks—from 1 to 4. For each performer, the table indicates the number of audience members who assigned each rank to the given performer. For example, exactly 49 audience members assigned rank 4 to Performer A. Two methods—the Mode Method and the Median Method—are used to assign final ranks to the performers based on these audience rankings.

Mode Method: Assign to each performer a final rank equal to the audience rank the performer received most often.

Median Method: Compute the median audience ranking for each performer. The ordering of the final rankings will be the same as the ordering of these medians.

­
Rank
Performer1234
A510049
B235720
C59500
D2102851
(Sort ↕ the table by clicking on the headers)­
________________________________________________________________
For each of the following final ranks, select Same if the two final ranking methods assigned the same performer the given rank. Otherwise, select Not same.


Rank 1

Using the mode method for Rank 1, we see that the only performer who received Rank 1 most often was Performer A, who received Rank 1 from 51 audience members.

Also, the median ranking for Performer A was Rank 1 since over half of Performer A's rankings were Rank 1, so the middle ranking for Performer A was Rank 1. Also, no other performer had a median ranking of Rank 1.

So, Performer A was assigned Rank 1 both ways.

Select Same.

Rank 2

Using the mode method for Rank 2, we see that the only performer who received Rank 2 most often was Performer C, who received Rank 2 from 95 audience members.

Also, the median ranking for Performer C was Rank 2 since over half of Performer C's rankings were Rank 2, so the middle ranking for Performer C was Rank 2. Also, no other performer had a median ranking of Rank 2.

So, Performer C was assigned Rank 2 both ways.

Select Same.

Rank 3

Using the mode method for Rank 3, we see that the only performer who received Rank 3 most often was Performer B, who received Rank 3 from 7 2 audience members.

Also, the median ranking for Performer B was Rank 3 since over half of Performer B's rankings were Rank 3, so the middle ranking for Performer B was Rank 3. Also, no other performer had a median ranking of Rank 3.

So, Performer B was assigned Rank 3 both ways.

Select Same.

Correct answer: Same, Same, Same­
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