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In a sequence of 10 consecutive integers, what is the average of all n

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In a sequence of 10 consecutive integers, what is the average of all n  [#permalink]

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New post Updated on: 20 Feb 2018, 09:25
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A
B
C
D
E

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  85% (hard)

Question Stats:

87% (01:04) correct 13% (01:03) wrong based on 34 sessions

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In a sequence of 10 consecutive integers, what is the average of all numbers in sequence?

(1) The sum of the first 5 integers is 410
(2) The sum of the last 5 integers is 435

Originally posted by niteshwaghray on 21 May 2017, 22:52.
Last edited by chetan2u on 20 Feb 2018, 09:25, edited 1 time in total.
Corrected the OA
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Re: In a sequence of 10 consecutive integers, what is the average of all n  [#permalink]

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New post 22 May 2017, 05:20
10 consecutive integers can be written as: a, a+1, a+2, ... a+9
If we can figure out 'a', we get the answer.

Statement 1. Given that:
a + a+1 + .. a+4 = 410
We can get 'a' and thus the answer. Sufficient.

Statement 2. Given that:
a+5 + a+6 +... a+9 = 435
We can again get 'a' and thus the answer. Sufficient.

Answer should be D

(OA is given as C, I don't think that is correct. Can you please check)
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Re: In a sequence of 10 consecutive integers, what is the average of all n  [#permalink]

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New post 22 May 2017, 05:46
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Top Contributor
amanvermagmat wrote:
Answer should be D

(OA is given as C, I don't think that is correct. Can you please check)


I've seen this question before.
I think the author of the original question believes that consecutive integers need not mean ASCENDING consecutive integers.
That is, the author believes that 6, 5, 4, 3 are consecutive integers.
If this were true, then each statement would not be sufficient, since we don't know whether the consecutive integers are ascending or descending.


However, the official guide says this about consecutive integers

The numbers –2, –1, 0, 1, 2, 3, 4, 5 are consecutive integers. Consecutive integers can be represented by n, n + 1, n + 2, n + 3, . . . , where n is an integer.

This suggests to me that consecutive integers implies ASCENDING consecutive integers, which means the answer should be D

Cheers,
Brent
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Re: In a sequence of 10 consecutive integers, what is the average of all n  [#permalink]

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New post 22 May 2017, 05:50
1
OA is incorrect.

By both statements the avg can be found out.

n+(n+1)+(n+2)+(n+3)+(n+4)=410
(n+6)+(n+7)+(n+8)+(n+9)+(n+10)=435
Both equations can be used to derive n.
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Re: In a sequence of 10 consecutive integers, what is the average of all n &nbs [#permalink] 22 May 2017, 05:50
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