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In a sequence S, each term, after first term,

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In a sequence S, each term, after first term,  [#permalink]

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New post 20 Mar 2019, 20:25
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  75% (hard)

Question Stats:

19% (01:44) correct 81% (01:46) wrong based on 16 sessions

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In a sequence S, each term, after first term, is obtained by multiplying the previous term by a constant k, where k ≠ 1. How many terms in the sequence are less than 1?

A. 8th term in the sequence is 32

B. 2nd term in the sequence is \(\frac{1}{2}\)

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Re: In a sequence S, each term, after first term,  [#permalink]

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New post 21 Mar 2019, 08:45
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Neither statement could be sufficient alone. Using both, we know that we get the 8th term by multiplying the 2nd term by the constant k six times. So

32 = (1/2)*k^6
64 = k^6

But k can be 2 or -2. Since we'll get a lot of terms less than 1 when k = -2, and almost none when k = 2, the information is not sufficient.
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Re: In a sequence S, each term, after first term,   [#permalink] 21 Mar 2019, 08:45
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In a sequence S, each term, after first term,

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