GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 06 Dec 2019, 10:38

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In a sequence S, each term, after first term,

Author Message
TAGS:

### Hide Tags

Senior Manager
Joined: 17 Oct 2016
Posts: 257
Location: India
Concentration: General Management, Healthcare
GMAT 1: 640 Q40 V38
GMAT 2: 680 Q48 V35
GPA: 3.05
WE: Pharmaceuticals (Health Care)
In a sequence S, each term, after first term,  [#permalink]

### Show Tags

20 Mar 2019, 20:25
5
00:00

Difficulty:

75% (hard)

Question Stats:

25% (01:45) correct 75% (01:50) wrong based on 28 sessions

### HideShow timer Statistics

In a sequence S, each term, after first term, is obtained by multiplying the previous term by a constant k, where k ≠ 1. How many terms in the sequence are less than 1?

A. 8th term in the sequence is 32

B. 2nd term in the sequence is $$\frac{1}{2}$$

_________________
_____________________
Chasing the dragon
GMAT Tutor
Joined: 24 Jun 2008
Posts: 1829
Re: In a sequence S, each term, after first term,  [#permalink]

### Show Tags

21 Mar 2019, 08:45
1
Neither statement could be sufficient alone. Using both, we know that we get the 8th term by multiplying the 2nd term by the constant k six times. So

32 = (1/2)*k^6
64 = k^6

But k can be 2 or -2. Since we'll get a lot of terms less than 1 when k = -2, and almost none when k = 2, the information is not sufficient.
_________________
GMAT Tutor in Toronto

If you are looking for online GMAT math tutoring, or if you are interested in buying my advanced Quant books and problem sets, please contact me at ianstewartgmat at gmail.com
Re: In a sequence S, each term, after first term,   [#permalink] 21 Mar 2019, 08:45
Display posts from previous: Sort by