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# In a set of consecutive integers the least number is – 23. If the aver

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Joined: 02 Sep 2009
Posts: 43335

Kudos [?]: 139513 [0], given: 12794

In a set of consecutive integers the least number is – 23. If the aver [#permalink]

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02 Jan 2018, 22:41
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In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23
[Reveal] Spoiler: OA

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Kudos [?]: 139513 [0], given: 12794

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Joined: 25 Feb 2013
Posts: 813

Kudos [?]: 381 [0], given: 42

Location: India
GPA: 3.82
In a set of consecutive integers the least number is – 23. If the aver [#permalink]

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03 Jan 2018, 03:22
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Bunuel wrote:
In a set of consecutive integers the least number is –23. If the average (arithmetic mean) of the set is 1, what is the greatest value in the set?

A. 27
B. 26
C. 25
D. 24
E. 23

Sum of $$n$$ consecutive integers $$= \frac{n(-23+last term)}{2}$$ (here last term of the series will have the greatest value)

Therefore average of $$n$$ terms $$= \frac{n(-23+last term)}{2n}=1$$

$$=> -23+Last term=2 => last Term=25$$

Option C

Kudos [?]: 381 [0], given: 42

In a set of consecutive integers the least number is – 23. If the aver   [#permalink] 03 Jan 2018, 03:22
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# In a set of consecutive integers the least number is – 23. If the aver

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