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01 May 2020, 11:03
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (02:23) correct
50%
(02:38)
wrong
based on 34
sessions
History
Date
Time
Result
Not Attempted Yet
In a triangle ABC, AB = 20 cm, AC = 20 cm, and BC = 30 cm. What is the length of the perpendicular from point B to side AC?
A. 15√7
B. 12√7
C. 10√7
D. 8√7
E. 7.5√7
A. 15√7
B. 12√7
C. 10√7
D. 8√7
E. 7.5√7
01 May 2020, 13:36
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\(AD = \sqrt{20^2 - 15^2}\)
\(AD = \sqrt{175}\)
\(AD = 5\sqrt{7}\)
Area of ABC =\(\frac{ 1}{2} * AD * BC = \frac{1}{2} * BE * AC\)
\(BE = \frac{AD * BC}{ AC}\)
\(BE = \frac{5\sqrt{7} * 30 }{ 20 }\) = \(7.5√7\)
\(AD = \sqrt{175}\)
\(AD = 5\sqrt{7}\)
Area of ABC =\(\frac{ 1}{2} * AD * BC = \frac{1}{2} * BE * AC\)
\(BE = \frac{AD * BC}{ AC}\)
\(BE = \frac{5\sqrt{7} * 30 }{ 20 }\) = \(7.5√7\)
Bunuel
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02 May 2020, 05:20
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Bunuel
The problem here is quite simple yet it gives us a good learning.
Here is the video solution for the step-by-step approach to the question and which answers the question
"How to start?"
Attachments
Screenshot 2020-05-02 at 5.46.04 PM.png [ 750.46 KiB | Viewed 8757 times ]
