VandyonWheels wrote:
In how many ways can 3 people out of 14 people be given 3 prizes(gold,silver,bronze) so that Jack is awarded? Jack is one of 14 people.
The given answer is
but I have not been able to understand how.
The direction that I proceeded was:
Jack gets gold or jack gets silver or jack gets bronze
=\(13*12 + 13*12 + 13*12\)
This seems to be wrong,so if somebody could explain where I'm going wrong and how to arrive at the correct answer it would be great!
Please help!
Since Jack has to be given an award so we need two more individuals out of rest 13 candidates
Those two candidates may be selected in 13C2 = 78 ways
Now we have team of 3 candidates (Jack included) and three persons can be given three different rewards in 3*2*1 = 3! = 6 ways
Total favourable ways = 78*6 = 468
Bunuel The following options may be given to the question (with C being the correct Answer)
A) 2184
B) 546
C) 468
D) 364
E) 156
Added the options. Thank you.