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Bunuel
In how many ways can 6 boys be allotted into 5 rooms such that no room is empty and all 6 boys are accommodated?

A. 27
B. 720
C. 840
D. 900
E. 1800


Are You Up For the Challenge: 700 Level Questions

For no room to be empty, 2 boys will be allotted to 1 room and the remaining 4 rooms will have 1 boys each.
Ways to allocate 2 boys to 1st room = 6C2 = 15
Ways to allocate 1 boy to 2nd room = 4C1
Ways to allocate 1 boy to 3rd room = 3C1
Ways to allocate 1 boy to 4th room = 2C1
Ways to allocate 1 boy to 5th room = 1C1

Total ways = 15*4*3*2 = 360
Since any one of the 5 rooms can hold 2 boys,multiply result by 5 = 360*5 = 1800
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