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Since all 7 chocolates are distinct and independent:
Total ways =
3 × 3 × 3 × 3 × 3 × 3 × 3
= 3^7
= 2187

ExpertsGlobal5
In how many ways can 7 different chocolates be distributed among 3 children if each child can get any number of chocolates?

A. 35
B. 84
C. 120
D. 210
E. 2187

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ExpertsGlobal5
In how many ways can 7 different chocolates be distributed among 3 children if each child can get any number of chocolates?

A. 35
B. 84
C. 120
D. 210
E. 2187
E is the correct answer choice.

Video explanation:

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If any number of chocolates can be distributed why is 0 not a possibility and accordingly the answer should be 4^7 ?
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suntprovident
If any number of chocolates can be distributed why is 0 not a possibility and accordingly the answer should be 4^7 ?

3^7 already includes the cases in which one child or even two children get 0 chocolates.

For each chocolate, there are only 3 choices: give it to child 1, child 2, or child 3.

0 chocolates for a child happens automatically when none of the 7 chocolates is assigned to that child.

So we do not need a fourth choice.
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