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Re: In how many ways can letters the word ATTITUDE be rearranged such that [#permalink]
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Bunuel wrote:
In how many ways can letters the word ATTITUDE be rearranged such that no two Ts are adjacent to each other?

A. 1800
B. 2400
C. 3600
D. 4320
E. 6720

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Asked: In how many ways can letters the word ATTITUDE be rearranged such that no two Ts are adjacent to each other?

A-1
T-3
I-1
U-1
D-1
E-1

Total words formed with letters of ATTITUDE = 8!/3! = 8*7!/6 = 4/3* 7! = 6720

Words in which 2 Ts are adjacent to one another = 7! = 5040

A-1
2T-1
T-1
I-1
U-1
D-1
E-1

But this includes the case when all 3 Ts are together and considers <2T>T & T<2T> as separate cases and are counted twice.

Words in which 3 Ts are adjacent to one another = 6! = 120

Words in which one or more Ts are adjacent to one another = 7! - 6! = 6*6! = 4320

Words in which no Ts are adjacent to one another = 6720 - 4320 = 2400

IMO B
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Re: In how many ways can letters the word ATTITUDE be rearranged such that [#permalink]
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Bunuel wrote:
In how many ways can letters the word ATTITUDE be rearranged such that no two Ts are adjacent to each other?

A. 1800
B. 2400
C. 3600
D. 4320
E. 6720

Take the task of seating the letters and break it into stages.

Stage 1: Arrange the non-T letters (A, I, U, D and E)
Since n unique objects can be arranged in n! ways, we can arrange these five letters in 5! ways. In other words, we can complete stage 1 in 120 ways.

Key step: For each arrangement of the 5 non-T letters, add a space on each side of each letter. So, for example, if we add spaces to the arrangement ADIUE, we get: _A_D_I_U_E_

Each of these six spaces represents a possible location for each of the 3 T's. Notice that this configuration ensures that no T's can be adjacent.

Stage 2: Place T's in 3 of the 6 available spaces .
IMPORTANT: Since we're placing 3 identical T's, the order in which select the 3 spaces doesn't matter.
So, we can use combinations.
We can choose 3 of the 6 spaces in 6C3 ways (= 20 ways)
So, we can complete stage 2 in 20 ways.

At this point, we'll throw away the remaining spaces, leaving an arrangement with all 8 letters.

By the Fundamental Counting Principle (FCP), the number of ways to complete the 2 stages (and thus place all 7 letters) = (120)(20) = 2,400 ways.

Answer: B

Cheers,
Brent
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