Last visit was: 13 Jul 2025, 06:41 It is currently 13 Jul 2025, 06:41
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
 1   2   
User avatar
hussi9
User avatar
Joined: 28 Mar 2010
Last visit: 05 Mar 2020
Posts: 128
Own Kudos:
512
 [65]
Given Kudos: 25
Status:GMAT in 4 weeks
GPA: 3.89
Posts: 128
Kudos: 512
 [65]
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 06:55
1
Kudos
Add Kudos
64
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

45% (medium)

Question Stats:

68% (02:11) correct 32% (02:34) wrong based on 366 sessions

History

Date
Time
Result
Not Attempted Yet
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------
ShowHide Answer
Official Answer
D
Most Helpful Reply
User avatar
umg
User avatar
Current Student
Joined: 18 Jun 2016
Last visit: 26 Jun 2020
Posts: 216
Own Kudos:
660
 [14]
Given Kudos: 111
Location: United States (NY)
GMAT 1: 720 Q50 V38
GMAT 2: 750 Q49 V42
GPA: 4
WE:General Management (Other)
Products:
My Reviews
GMAT 2: 750 Q49 V42
Posts: 216
Kudos: 660
 [14]
In how many ways can the letters of the word JUPITER be arranged in a 30 Apr 2017, 11:27
8
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------
Though I got it wrong, Here is the best Method to solve this question.

JUPITER -> 7 Alphabets -> 3 Vowels and 4 Consonants.

# Arrangements of 3 Vowels = 3! = 6.
# of Valid arrangements out of these = 1 For all the other arrangements, vowels will not be arranged alphabetically.

Number of Legitimate Arrangements = Total Arrangements - Illegitimate arrangements.

\(= 7! - \frac{5}{6}*7!\)
\(= 7!*(1 - \frac{5}{6})\)
\(=7! * \frac{1}{6}\)
= 840
avatar
debtanuB
avatar
Joined: 22 Feb 2017
Last visit: 09 Oct 2021
Posts: 29
Own Kudos:
39
 [14]
Given Kudos: 141
Affiliations: National Institute of Technology, Durgapur
Location: India
GPA: 3.6
WE:Engineering (Manufacturing)
Posts: 29
Kudos: 39
 [14]
In how many ways can the letters of the word JUPITER be arranged in a 23 Jan 2019, 00:07
8
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
Kem12
I have really tried to understand the concepts applied here from all the explanations but I still don't.Can someone be kind enough to help with a link that explains these concepts clearly...:-(:-(

Thanks.

Posted from my mobile device

If you are struggling with the above methods like me, I'm going to explain to you my way of solving ; However I don't know whether it would be sufficient to clear your doubts or not ?!

There are a TOTAL '7-seats' for the alphabets of the letter 'JUPITER' out of which '3' are vowels & '4' are consonants ;

The question asks us to find the total no. of ways in which vowels will be in a particular order (,i.e, alphabetical order & if it was a no. code maybe the question would have told ascending/descending order) ;

Coming back to the question, we know there are '7-seats' => We have to choose '3-seats' for our vowels ( E, I, & U ) => we can do that in 7C3 ways ;
Or, simply [7!/(3!x4!)] ways [This is what I meant => C C V V V C C, C V C V C V C, C C C V V V C, etc.]
Now, the order of vowels is 'E I U' => Total no. of arrangements = (7C3 x 1)
[And NOT (7C3 x 3!) Since, doing so we would include the arrangements 'UIE, UEI, IUE, IEU, EUI' along with 'EIU' which we don't want as per the question]

Now, we are left with '4-seats' for consonants (J, P,T, & R) => We can choose '4-seats' for '4' consonants in 4C4 (or 1) way ;
[But here we are allowed for arrangements, i.e, JEUITPR, JEUITRP, EUIJPRT, EUITPR, etc] ;
Hence, we can do it in 4C4x4! ways ;

THEREFORE, TOTAL NO. of WAYS IN WHICH VOWELS STAYS IN ALPHABETICAL ORDER IN 'JUPITER' = 7C3x1x4C4x4! = 840 ways = option D.
Hope it helps... :) :)
General Discussion
User avatar
amit2k9
User avatar
Joined: 08 May 2009
Last visit: 18 Jun 2017
Posts: 538
Own Kudos:
625
 [3]
Given Kudos: 10
Status:There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Posts: 538
Kudos: 625
 [3]
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 08:12
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
three letters can be arranged in 3! ways.
only one combination EIU is required.

7 letters can be arranged in 7! ways.

thus 7!/ 3! * 1 = 840.

D
User avatar
subhashghosh
User avatar
Retired Moderator
Joined: 16 Nov 2010
Last visit: 25 Jun 2024
Posts: 899
Own Kudos:
1,253
Given Kudos: 43
Location: United States (IN)
Concentration: Strategy, Technology
Products:
My Reviews
Posts: 899
Kudos: 1,253
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 08:51
Kudos
Add Kudos
Bookmarks
Bookmark this Post
@amit2k9, could you please explain this in more detail ?
User avatar
amit2k9
User avatar
Joined: 08 May 2009
Last visit: 18 Jun 2017
Posts: 538
Own Kudos:
625
 [5]
Given Kudos: 10
Status:There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Posts: 538
Kudos: 625
 [5]
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 11:10
3
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
1. Consider EIU as one. then total possible combination of words = 5* 4! = 120

2. Consider EI and IU together total possible combinations = [5 (positions for EI out of 7) * 5! (rest of the letters)] +

[ 5 (positions for IU)* 5! (rest of the letters)]

Now in half of the combinations U will be ahead of EI and E will be ahead of IU.

So 1/2[5 (positions for EI out of 7) * 5! (rest of the letters)] +1/2 [ 5 (positions for IU)* 5! (rest of the letters)]

total will give = 300 + 300 = 600.

3. Consider E-I-U-- with one letter spacing in between = 3(positions of EIU shifting) * 4! (letters to be arranged) = 72

4. Consider E-I--U- and E---I-U with two letter spacing between IU and EI = 2 * 4! = 48

thus totaling 120 + 600 + 72 + 48 = 840.


Alternately , Consider

all possible letter arrangements = 7!

only one combination out of 3! combinations possible for EIU. meaning 3 are taken in a group,but they are not alike.
Means total combinations remain 7! and not 5! ( EIU together + 4 letters).

So, essentially it is 7P3 =
Hence 7!/ 3! = 840
User avatar
bellcurve
User avatar
Joined: 19 Nov 2010
Last visit: 19 Mar 2014
Posts: 63
Own Kudos:
258
Given Kudos: 9
Posts: 63
Kudos: 258
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 13:51
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Amt2k9,

Conceptwise, I did not get your 7!/3!. If the word was, Let's say JUPUTUR, number of ways the letter can be arranged is 7!/3! ways (total ! / identical !). You used the same concept where the letters are not identical. You mentioned that those are not alike, but still not clear on why we still can do 7!/3!.
User avatar
gmat1220
User avatar
Joined: 03 Feb 2011
Last visit: 17 Feb 2020
Posts: 466
Own Kudos:
963
 [1]
Given Kudos: 123
Status:Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Products:
My Reviews
Posts: 466
Kudos: 963
 [1]
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 19:20
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Darn ! I am not Amt2k9. I think it is pretty obvious that in 1/6th of the ways out of 7! the vowels will be ordered. This reasoning is parallel to the situation when we have 3 people lets say A B C sitting in a row and we want to know the ways in which they will be alphabetical order. There is just one way ie. 3!/6=1 or 3!/3!

The division by 3! is NOT owned by the concept of weeding out the duplicates. We will apply it when we need it :wink:

bellcurve
Amt2k9,

Conceptwise, I did not get your 7!/3!. If the word was, Let's say JUPUTUR, number of ways the letter can be arranged is 7!/3! ways (total ! / identical !). You used the same concept where the letters are not identical. You mentioned that those are not alike, but still not clear on why we still can do 7!/3!.
User avatar
hussi9
User avatar
Joined: 28 Mar 2010
Last visit: 05 Mar 2020
Posts: 128
Own Kudos:
512
 [1]
Given Kudos: 25
Status:GMAT in 4 weeks
GPA: 3.89
Posts: 128
Kudos: 512
 [1]
In how many ways can the letters of the word JUPITER be arranged in a 20 May 2011, 23:27
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
bellcurve
Amt2k9,

Conceptwise, I did not get your 7!/3!. If the word was, Let's say JUPUTUR, number of ways the letter can be arranged is 7!/3! ways (total ! / identical !). You used the same concept where the letters are not identical. You mentioned that those are not alike, but still not clear on why we still can do 7!/3!.


Since the order of vowels will always remain the same despite these occupying different positions -> if we assume each vowel as X then our question is same as asking "arrange JPTRXXX" => in all 7!/3! ways
=> Choice (4) is the right answer
User avatar
DAllison2016
User avatar
Joined: 07 Jul 2016
Last visit: 30 Sep 2016
Posts: 58
Own Kudos:
66
 [2]
Given Kudos: 51
GPA: 4
Posts: 58
Kudos: 66
 [2]
In how many ways can the letters of the word JUPITER be arranged in a 05 Aug 2016, 23:44
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876

Commenting as I struggled getting my head around the concept. Kudos given above.

There are \(7_P7 = 7!\) ways to arrange the 7 letters.

For each of these combinations, there is a single valid arrangement of the vowels: \(\frac{1}{3_P3}\)

\(7! \times \frac{1}{3!} = \frac{7!}{3!} = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!} = 840 = D\)
User avatar
shashankism
User avatar
Joined: 13 Mar 2017
Last visit: 23 Dec 2024
Posts: 611
Own Kudos:
670
 [4]
Given Kudos: 88
Affiliations: IIT Dhanbad
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE:Engineering (Energy)
Posts: 611
Kudos: 670
 [4]
In how many ways can the letters of the word JUPITER be arranged in a 05 Jul 2017, 05:43
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------

Without limitation the words of JUPITER can be arranged in 7! ways..
Now there are 3 vowels I, E, U

So these vowels can be arranged among themselves in 3! ways.
We need to find the arrangement in vowels are in alphabetical order i.e. EIU which is only one out of 3! ways.

Hence, total number of required arrangement = 7!/3! = 7*6*5*4 = 42 * 20 = 840

Answer D
User avatar
Kem12
User avatar
Joined: 18 Apr 2018
Last visit: 01 Feb 2021
Posts: 70
Own Kudos:
34
Given Kudos: 211
Posts: 70
Kudos: 34
In how many ways can the letters of the word JUPITER be arranged in a 09 Dec 2018, 01:58
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have really tried to understand the concepts applied here from all the explanations but I still don't.Can someone be kind enough to help with a link that explains these concepts clearly...:-(:-(

Thanks.

Posted from my mobile device
User avatar
Kem12
User avatar
Joined: 18 Apr 2018
Last visit: 01 Feb 2021
Posts: 70
Own Kudos:
34
Given Kudos: 211
Posts: 70
Kudos: 34
In how many ways can the letters of the word JUPITER be arranged in a 23 Jan 2019, 04:13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Lithium
Kem12
I have really tried to understand the concepts applied here from all the explanations but I still don't.Can someone be kind enough to help with a link that explains these concepts clearly...:-(:-(

Thanks.

Posted from my mobile device

If you are struggling with the above methods like me, I'm going to explain to you my way of solving ; However I don't know whether it would be sufficient to clear your doubts or not ?!

There are a TOTAL '7-seats' for the alphabets of the letter 'JUPITER' out of which '3' are vowels & '4' are consonants ;

The question asks us to find the total no. of ways in which vowels will be in a particular order (,i.e, alphabetical order & if it was a no. code maybe the question would have told ascending/descending order) ;

Coming back to the question, we know there are '7-seats' => We have to choose '3-seats' for our vowels ( E, I, & U ) => we can do that in 7C3 ways ;
Or, simply [7!/(3!x4!)] ways [This is what I meant => C C V V V C C, C V C V C V C, C C C V V V C, etc.]
Now, the order of vowels is 'E I U' => Total no. of arrangements = (7C3 x 1)
[And NOT (7C3 x 3!) Since, doing so we would include the arrangements 'UIE, UEI, IUE, IEU, EUI' along with 'EIU' which we don't want as per the question]

Now, we are left with '4-seats' for consonants (J, P,T, & R) => We can choose '4-seats' for '4' consonants in 4C4 (or 1) way ;
[But here we are allowed for arrangements, i.e, JEUITPR, JEUITRP, EUIJPRT, EUITPR, etc] ;
Hence, we can do it in 4C4x4! ways ;

THEREFORE, TOTAL NO. of WAYS IN WHICH VOWELS STAYS IN ALPHABETICAL ORDER IN 'JUPITER' = 7C3x1x4C4x4! = 840 ways = option D.

Hope it helps... :) :)
Thank you so much
:blushing this was so helpful
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 11 Jul 2025
Posts: 16,101
Own Kudos:
74,300
 [1]
Given Kudos: 475
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,101
Kudos: 74,300
 [1]
In how many ways can the letters of the word JUPITER be arranged in a 23 Jan 2019, 04:36
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------

Alternatively, think of it this way:

The vowels must be arranged like this:

E I U
Now there are 4 spots (shown by x) for J:
x E x I x U x
Say we choose E J I U

Next we place P. There are 5 spots for P:
x E x J x I x U x

and so on for T and R too.

So in all we get 4*5*6*7 = 840 different ways (you don't need to calculate this. Since there is a 2 and 5, it will end in 0)

Answer (D)
User avatar
Archit3110
User avatar
Major Poster
Joined: 18 Aug 2017
Last visit: 13 July 2025
Posts: 8,347
Own Kudos:
4,823
Given Kudos: 243
Status:You learn more from failure than from success.
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1: 545 Q79 V79 DI73
GPA: 4
WE:Marketing (Energy)
GMAT Focus 1: 545 Q79 V79 DI73
Posts: 8,347
Kudos: 4,823
In how many ways can the letters of the word JUPITER be arranged in a 23 Jan 2019, 04:50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------

JUPITER
total 7 ! is the ways it can be arranged
but question has asked vowels appear in alphabetical order
so
EIUJPTR would be the sequence
we can put EIU ; 3!

7!/3! = 840

IMO D
User avatar
mischiefmanaged
User avatar
Joined: 04 Oct 2016
Last visit: 11 Apr 2019
Posts: 14
Own Kudos:
5
Given Kudos: 120
Posts: 14
Kudos: 5
In how many ways can the letters of the word JUPITER be arranged in a 24 Jan 2019, 20:15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------

Alternatively, think of it this way:

The vowels must be arranged like this:

E I U
Now there are 4 spots (shown by x) for J:
x E x I x U x
Say we choose E J I U

Next we place P. There are 5 spots for P:
x E x J x I x U x

and so on for T and R too.

So in all we get 4*5*6*7 = 840 different ways (you don't need to calculate this. Since there is a 2 and 5, it will end in 0)

Answer (D)

Hi VeritasKarishma,
Kindly, help me understand why P has 5 spots and so on.
J has 4 spots and then should't be 3 spots for P and so on...
Please help!
User avatar
KanishkM
User avatar
Joined: 09 Mar 2018
Last visit: 18 Dec 2021
Posts: 765
Own Kudos:
492
Given Kudos: 123
Location: India
Schools: DeGroote'21 Desautels '21 NUS '21
Schools: DeGroote'21 Desautels '21 NUS '21
Posts: 765
Kudos: 492
In how many ways can the letters of the word JUPITER be arranged in a Updated on: 24 Jan 2019, 20:57
Originally posted by KanishkM on 24 Jan 2019, 20:39.
Last edited by KanishkM on 24 Jan 2019, 20:57, edited 1 time in total.
Kudos
Add Kudos
Bookmarks
Bookmark this Post
hussi9
In how many ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?

(A) 736
(B) 768
(C) 792
(D) 840
(E) 876


------------------------------------------------------
IIM CAT Level Question
------------------------------------------------------

I solved this question,in the inline way
i fixed the position of E
E _ _ _ _ _ _, Now here if I U takes the 1st 2 spots Then the remaining spots will be filled in 4*3*2*1 = 24 ways and I U can move 4 more times making the total ways as 24*5 = 120 ways

In the next case I will fix E I this time and move the rest of the alphabets i.e. E I _ U _ _ _ and so on, this will give you 96 ways.

Next Case, I fixed E I U, this will give you 24 ways.

Total = 120 + 96 + 24= 240, now EIU can also be UIE, this makes 240*2 ways = 840 ways

OA D
avatar
Valhalla
avatar
Joined: 26 Apr 2017
Last visit: 29 Nov 2022
Posts: 39
Own Kudos:
145
Given Kudos: 71
Posts: 39
Kudos: 145
In how many ways can the letters of the word JUPITER be arranged in a 24 Jan 2019, 20:44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
amit2k9
1. Consider EIU as one. then total possible combination of words = 5* 4! = 120

2. Consider EI and IU together total possible combinations = [5 (positions for EI out of 7) * 5! (rest of the letters)] +

[ 5 (positions for IU)* 5! (rest of the letters)]

Now in half of the combinations U will be ahead of EI and E will be ahead of IU.

So 1/2[5 (positions for EI out of 7) * 5! (rest of the letters)] +1/2 [ 5 (positions for IU)* 5! (rest of the letters)]

total will give = 300 + 300 = 600.

3. Consider E-I-U-- with one letter spacing in between = 3(positions of EIU shifting) * 4! (letters to be arranged) = 72

4. Consider E-I--U- and E---I-U with two letter spacing between IU and EI = 2 * 4! = 48

thus totaling 120 + 600 + 72 + 48 = 840.


Alternately , Consider

all possible letter arrangements = 7!

only one combination out of 3! combinations possible for EIU. meaning 3 are taken in a group,but they are not alike.
Means total combinations remain 7! and not 5! ( EIU together + 4 letters).

So, essentially it is 7P3 =
Hence 7!/ 3! = 840

amit2k9
1. Consider EIU as one. then total possible combination of words = 5* 4! = 120

2. Consider EI and IU together total possible combinations = [5 (positions for EI out of 7) * 5! (rest of the letters)] +

[ 5 (positions for IU)* 5! (rest of the letters)]

Now in half of the combinations U will be ahead of EI and E will be ahead of IU.

So 1/2[5 (positions for EI out of 7) * 5! (rest of the letters)] +1/2 [ 5 (positions for IU)* 5! (rest of the letters)]

total will give = 300 + 300 = 600.

3. Consider E-I-U-- with one letter spacing in between = 3(positions of EIU shifting) * 4! (letters to be arranged) = 72

4. Consider E-I--U- and E---I-U with two letter spacing between IU and EI = 2 * 4! = 48

thus totaling 120 + 600 + 72 + 48 = 840.


Alternately , Consider

all possible letter arrangements = 7!

only one combination out of 3! combinations possible for EIU. meaning 3 are taken in a group,but they are not alike.
Means total combinations remain 7! and not 5! ( EIU together + 4 letters).

So, essentially it is 7P3 =
Hence 7!/ 3! = 840


Sent from my Moto G (5) Plus using GMAT Club Forum mobile app
avatar
KarimAzhikulov
avatar
Joined: 26 Jan 2021
Last visit: 28 Jun 2021
Posts: 2
Given Kudos: 38
Posts: 2
Kudos: 0
In how many ways can the letters of the word JUPITER be arranged in a 08 Jun 2021, 00:36
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello!
Here is my approach

Consonants can be arranged in 4!=24 ways leaving 5 places for Vowels _J_P_T_R_

There are 4 possible scenarios for the only alowed Vowels sequence EIU:
1. EIU as single solid unit goes into one of 5 available places = 5×4!=120
2. Each of E, I, and U take one of 5 available places between Consonants. So we need to choose 3 out of 5 = 5C3×4!=10×24=240
3. EI and U accomodate 2 out of 5 available places. So we choose 2 out of 5 = 5C2×4!=10×4!=240
4. E and IU accomodate 2 out of 5 available places. 5C2×4!=10×4!=240

120+240+240+240=840
User avatar
bv8562
User avatar
Joined: 01 Dec 2020
Last visit: 11 Jul 2025
Posts: 437
Own Kudos:
464
Given Kudos: 359
GMAT 1: 680 Q48 V35
GMAT 1: 680 Q48 V35
Posts: 437
Kudos: 464
In how many ways can the letters of the word JUPITER be arranged in a 30 Jun 2021, 09:19
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is how I solved this:

First we can select 4 places out of 7 places for placing CONSONANTS and at these 4 places CONSONANTS can be arranged in 4! ways and at the remaining places we can select each vowel alphabetically and place them in alphabetic order i.e:

7C4 * 4! * 1C1 *1C1 * 1C1 = 35 * 24 = 840 (D)
 1   2   
Moderators:
Bunuel
Math Expert
102638 posts
Krunaal
PS Forum Moderator
690 posts